【发布时间】：2013-12-30 13:54:40
【问题描述】：
我有这个程序要求用户输入信息，并将其存储在文件中，并允许您通过将总工资设置为 0 来编辑条目或添加新条目或删除条目。
但是，当我尝试修改名称时，它不会修改，当我尝试修改性别时，它会导致无限循环，任何人都可以告诉我有什么问题吗？
我认为我在循环中所做的 break 语句有问题，在此先感谢
#include <stdio.h>
#include <stdlib.h>
typedef struct
{
int employee_number;
char employee_name[20];
char employee_sex;
int employee_gross_salary;
}information;
int main()
{//open main function
information customer;
int i;
int choice;
int number;
int choice2;
int number2;
FILE *fptr = fopen("emp.dat", "wb+");
//asking user to enter atleast 5 customers into datarecords
for(i = 0; i<1;i++)
{//open for
printf("enter employee's number\n");
scanf("%d",&customer.employee_number);
getchar();
printf("enter the employee's name\n");
scanf("%s", customer.employee_name);
getchar();
printf("enter employee's gender\n");
scanf("%d",&customer.employee_sex);
getchar();
printf("enter employee's salary\n");
scanf("%d",&customer.employee_gross_salary);
getchar();
fwrite(&customer,sizeof(customer),1,fptr);
}//close for
for(;;)
{//open for
printf("\n what would you like to do\n1]Add entry\n 2]Delete entry \n3]Modify entry\n4]view entries\n5]exit\n");
scanf("%d", &choice);
if(choice == 5)
{break;}
else if(choice == 1)
{//open else if
fseek(fptr,0, SEEK_END);// check the parameters here
printf("enter new employee's number\n");
scanf("%d",&customer.employee_number);
getchar();
printf("enter the new employee's name\n");
scanf("%s", customer.employee_name);
getchar();
printf("enter new employee's gender\n");
scanf("%d",&customer.employee_sex);
getchar();
printf("enter new employee's salary\n");
scanf("%d",&customer.employee_gross_salary);
getchar();
fwrite(&customer,sizeof(customer),1,fptr);
continue;
}//close else if
else if( choice == 2)
{//open else if
printf("enter the employee number of person\n");
scanf("%d",&number);
fseek(fptr,0,SEEK_SET);
while((fread(&customer,sizeof(customer), 1,fptr))!=NULL)
{//open while
if(customer.employee_number == number)
{//open if
customer.employee_gross_salary = 0;
}//close if
}//close while
continue;
}//clsoe else if
else if(choice == 3)
{//open else if
printf("enter the employee number of the employee you would like to modify\n");
scanf("%d",&number2);
printf("what would you like to modify\n");
scanf("%d", &choice2);
fseek(fptr,0,SEEK_SET);
while((fread(&customer, sizeof(customer),1,fptr))!= NULL)
{//open while within else if
//1 to midify name, 2 to modify gender 3 for salary
if(customer.employee_number == number2)
{//open if
if(choice2 == 1)
{
printf("enter new name\n");
scanf("%s",customer.employee_name );
break;
}
else if(choice2 == 2)
{
printf("enter new gender");
scanf("%d", &customer.employee_sex);
break;
}
else if(choice2 == 3)
{
printf("enter new gross salary\n");
scanf("%d", &customer.employee_gross_salary);
break;
}
}//close if
}//close while within else if
continue;
}//close else if
else if(choice == 4)
{
fseek(fptr,0,SEEK_SET);
while((fread(&customer,sizeof(customer),1,fptr))!= NULL)
printf("\n%d\t%s\t%c\t%d\n", customer.employee_number,customer.employee_name,customer.employee_sex,customer.employee_gro ss_salary);
continue;
}
}//close for
return 0;
}//close main function
【问题讨论】：
-
标题灼伤我的眼睛，还有短信说话
-
尝试用小代码重现您的问题。有了这个，你会更快得到你的答案
-
@nrathaus jst 如果 itz 不是 insd StkOvrfl0w
-
@Bartdude 无限循环——也许这就是核心问题；）
-
为什么不自己调试代码呢？我认为这是解决这个问题的方法。你应该知道如何调试
标签： c