如何根据一天中的任务完成情况从给定日期列中获取开始日期和结束日期（oracle）

Question

这里在dummy data中，你可以看到有两列Task_Completion和Time_stamp。有一个java scheduler在任务完成时运行，例如scheduler在 15-FEB-2016 上运行 5 次，并且仅在 17-FEB 上运行所以我想要一个查询来计算给定列 time_stamp

Task_Completion                     Time_stamp
true                     15-FEB-16 11.37.56.013000000 AM
true                     15-FEB-16 11.42.55.593000000 AM
true                     15-FEB-16 11.47.48.970000000 AM
true                     15-FEB-16 12.21.57.587000000 PM
true                     15-FEB-16 12.26.55.767000000 PM 
true                     17-FEB-16 10.24.03.320000000 PM
true                     18-FEB-16 10.19.04.333000000 PM

所以输出一定是这样的

       start_time                                      end_time
15-FEB-16 11.37.56.013000000 AM          15-FEB-16 11.47.48.970000000 AM
15-FEB-16 12.21.57.587000000 PM          15-FEB-16 12.26.55.767000000 PM 
17-FEB-16 10.21.33.320000000 PM          17-FEB-16 10.26.33.320000000 PM
18-FEB-16 10.16.33.333000000 PM          18-FEB-16 10.21.33.333000000 PM

有两个条件

条件 1. 如果在 time_stamp 中有 0-5 分钟 间隔，例如在 2 月 15 日那么 start_time 将是 11.37.56.013000000 并且 end_time 将是 11.47.48.970000000 但如果没有，那么再次检查当天是否有任何时间表运行，例如 2 月 15 日 12.21.57.587000000(start_time) 和 12.26.55.767000000(end_time)

condition2. 如果计划一天只运行一次，则平均该 time_stamp 并从该时间开始添加/减去 2.30 分钟（即) 无需再次检查

举例

2 月 17 日 10.21.33.320000000(start_time) 和 10.26.33.320000000(end_time) 与 2 月 18 日相同

所以我的逻辑是，将条件 1 和条件 2 合并，这就是我最终的结果......

--------------------condition2-------------------

select count(*), min(time_stamp) - interval '150' second start_date, max(time_stamp) + interval '150' second end_date
from serverstatus 
group by to_char(time_stamp,'dd-mon-yy')
having count(*)=1
UNION ALL

------------condition1 query--------------------------

我需要 Condition1 查询

Answer 1

SELECT start_time - CASE num_grp_per_day
                      WHEN 1
                      THEN INTERVAL '150' SECOND
                      ELSE INTERVAL '0' SECOND
                    END AS start_time,
       end_time   + CASE num_grp_per_day
                      WHEN 1
                      THEN INTERVAL '150' SECOND
                      ELSE INTERVAL '0' SECOND
                    END AS end_time
FROM   (
  SELECT DISTINCT
         MIN( time_stamp ) OVER ( PARTITION BY grp ) AS start_time,
         MAX( time_stamp ) OVER ( PARTITION BY grp ) AS end_time,
         COUNT( DISTINCT grp ) OVER ( PARTITION BY TRUNC( time_stamp ) ) AS num_grp_per_day
  FROM   (
    SELECT time_stamp,
           SUM( diff ) OVER ( ORDER BY time_stamp ) AS grp
    FROM   (
      SELECT time_stamp,
             CASE
               WHEN time_stamp - LAG( time_stamp ) OVER ( ORDER BY time_stamp )
                      <= INTERVAL '5' MINUTE
               THEN 0
               ELSE 1
             END AS diff
      FROM   your_table
    )
  )
)
ORDER BY start_time;

或者，如果您只想将所有零宽度组扩展到 5 分钟间隔（而不仅仅是每天有一个时），那么：

SELECT MIN( time_stamp ) - CASE COUNT(*)
                             WHEN 1
                             THEN INTERVAL '150' SECOND
                             ELSE INTERVAL '0' SECOND
                           END AS start_time,
       MAX( time_stamp ) + CASE COUNT(*)
                             WHEN 1
                             THEN INTERVAL '150' SECOND
                             ELSE INTERVAL '0' SECOND
                           END AS end_time
FROM   (
  SELECT time_stamp,
         SUM( diff ) OVER ( ORDER BY time_stamp ) AS grp
  FROM   (
    SELECT time_stamp,
           CASE
             WHEN time_stamp - LAG( time_stamp ) OVER ( ORDER BY time_stamp )
                    <= INTERVAL '5' MINUTE
             THEN 0
             ELSE 1
           END AS diff
    FROM   your_table
  )
)
GROUP BY grp;