while循环重复了mysql表中数组的最后一行

Question

我想从我的 mysql 表中获取与我的查询匹配的所有行 截至目前，我有两行匹配查询我将每一行保存在 $tourData 变量，而不是在 while 循环中添加到 $allTourData 变量中。

这个函数在我的$allTourData 中返回两个数组，但是我得到了第一行和第二行两次。

这是我的代码。

public static function getTourAvailabilityStatus($date, $route)
{
    $lt   = MySQL::connect();
    $tour = $lt->prepare
    (   /** @lang MySQL */
        "
            SELECT id, token, route, date, travels_name, bus_number, st, aj, wt, sl
            FROM tour
            WHERE date = ? AND route = ? ;
            "
        );

    MySQL::error($tour, $lt);
    $tour->bind_param('ss', $date, $route);
    MySQL::error($tour, $lt);
    $tour->execute();
    MySQL::error($tour, $lt);
    $tourData = [];
    $tour->bind_result(
        $tourData['id'], $tourData['token'], $tourData['route'], $tourData['date'], $tourData['travelsName'],
        $tourData['BusNumber'], $tourData['st'], $tourData['aj'], $tourData['wt'], $tourData['sl']
    );
    MySQL::error($tour, $lt);
    $allTourData = [];
    while($tour->fetch())
    {
        $allTourData[] = $tourData;
    }
    MySQL::error($tour, $lt);
    $tour->close();

    return $allTourData;
}

Answer 1

这应该可以解决问题：

public static function getTourAvailabilityStatus($date, $route)
{
    $lt   = MySQL::connect();
    $tour = $lt->prepare
    (   /** @lang MySQL */
        "
            SELECT id, token, route, date, travels_name, bus_number, st, aj, wt, sl
            FROM tour
            WHERE date = ? AND route = ? ;
            "
        );

    MySQL::error($tour, $lt);
    $tour->bind_param('ss', $date, $route);
    MySQL::error($tour, $lt);
    $tour->execute();
    MySQL::error($tour, $lt);

    $tour->bind_result(
        $id, $token, $route, $date, $travelsName,$BusNumber, $st, $aj, $wt, $sl
    );
    MySQL::error($tour, $lt);
    $allTourData = [];
    while($tour->fetch())
    {
        $allTourData[] = [ $id, $token, $route, $date, $travelsName,$BusNumber, $st, $aj, $wt, $sl];
    }
    MySQL::error($tour, $lt);
    $tour->close();

    return $allTourData;
}