【发布时间】:2012-07-19 05:39:31
【问题描述】:
我有一个 iphone 应用程序,我在其中将推送通知作为警报视图。当我的应用程序处于后台状态时,推送通知即将到来,当我点击它或解锁手机时,它直接进入到我让它处于前台状态的应用程序。我正在通过单击视图按钮在警报中添加一个操作,它将转到另一个视图控制器。当我单击通知时,我不想进入应用程序。我需要显示警报视图,当单击视图按钮时,我需要执行我的操作。任何人都可以帮助我实现这一点。这是我的代码 sn-p `-
- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo
{
//check application in forground or background
if(application.applicationState == UIApplicationStateActive)
{
//NSLog(@"FOreGround");
//NSLog(@"and Showing %@",userInfo)
}
else
{
NSDictionary *curDict= [userInfo objectForKey:@"aps"];
UIAlertView *connectionAlert = [[UIAlertView alloc] initWithTitle:@"app" message:[NSString stringWithFormat:@"%@",[curDict objectForKey:@"alert"]] delegate:self cancelButtonTitle:@"View" otherButtonTitles:@"Cancel",nil];
[connectionAlert show];
[connectionAlert release];
[UIApplication sharedApplication].applicationIconBadgeNumber =[[curDict objectForKey:@"badge"] intValue];
}
}
- (void)applicationWillEnterForeground:(UIApplication *)application
{
NSLog(@"applicationWillEnterForeground");
[UIApplication sharedApplication].applicationIconBadgeNumber = 0;
}
- (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex
{
NSString *title = [alertView buttonTitleAtIndex:buttonIndex];
if ([title isEqualToString:@"View"])
{
NSArray *mycontrollers = self.tabBarController.viewControllers;
NSLog(@"%@",mycontrollers);
[[mycontrollers objectAtIndex:0] popToRootViewControllerAnimated:NO];
mycontrollers = nil;
tabBarController.selectedIndex = 0;
}
}
【问题讨论】:
-
抱歉,您能说得更准确点吗?触摸通知时不想进入应用程序?这根本不可能……
标签: iphone ios ipad apple-push-notifications