【发布时间】:2011-07-19 12:21:59
【问题描述】:
我正在尝试使用 AMQP、Websockets 和 Ruby 构建一个简单的聊天应用程序。我知道这可能不是理解 AMQP 的最佳用例,但我想了解我哪里出错了。
以下是我的 amqp-server 代码
require 'rubygems'
require 'amqp'
require 'mongo'
require 'em-websocket'
require 'json'
class MessageParser
# message format => "room:harry_potter, nickname:siddharth, room:members"
def self.parse(message)
parsed_message = JSON.parse(message)
response = {}
if parsed_message['status'] == 'status'
response[:status] = 'STATUS'
response[:username] = parsed_message['username']
response[:roomname] = parsed_message['roomname']
elsif parsed_message['status'] == 'message'
response[:status] = 'MESSAGE'
response[:message] = parsed_message['message']
response[:roomname] = parsed_message['roomname'].split().join('_')
end
response
end
end
class MongoManager
def self.establish_connection(database)
@db ||= Mongo::Connection.new('localhost', 27017).db(database)
@db.collection('rooms')
@db
end
end
@sockets = []
EventMachine.run do
connection = AMQP.connect(:host => '127.0.0.1')
channel = AMQP::Channel.new(connection)
puts "Connected to AMQP broker. #{AMQP::VERSION} "
mongo = MongoManager.establish_connection("trackertalk_development")
EventMachine::WebSocket.start(:host => '127.0.0.1', :port => 8080) do |ws|
socket_detail = {:socket => ws}
ws.onopen do
@sockets << socket_detail
end
ws.onmessage do |message|
status = MessageParser.parse(message)
exchange = channel.fanout(status[:roomname].split().join('_'))
if status[:status] == 'STATUS'
queue = channel.queue(status[:username], :durable => true)
unless queue.subscribed?
puts "--------- SUBSCRIBED --------------"
queue.bind(exchange).subscribe do |payload|
puts "PAYLOAD : #{payload}"
ws.send(payload)
end
else
puts "----ALREADY SUBSCRIBED"
end
# only after 0.8.0rc14
#queue = channel.queue(status[:username], :durable => true)
#AMQP::Consumer.new(channel, queue)
elsif status[:status] == 'MESSAGE'
puts "********************* Message- published ******************************"
exchange.publish(status[:message)
end
end
ws.onclose do
@sockets.delete ws
end
end
end
我使用状态来指示传入消息是用于正在进行的聊天的消息,还是需要我处理诸如订阅队列之类的杂务的状态消息。
我面临的问题是,当我发送消息时
socket.send(JSON.stringify({status:'message', message:'test', roomname:'Harry Potter'}))
exchange.publish' is called but it still doesn't get pushed via thews.send` 发送到浏览器。
我对 EventMachine 和 AMQP 的理解有什么根本错误吗?
这是相同代码http://pastie.org/private/xosgb8tw1w5vuroa4w7a的馅饼
当我从queue = channel.queue(status[:username], :durable => true) 中删除durable => true 时,我的代码似乎可以正常工作
以下是我的 Rails 视图的 sn-p,它识别用户的用户名和房间名,并通过 Websockets 作为消息的一部分发送。
虽然当我删除 durable => true 时代码似乎可以工作,但我不明白为什么这会影响正在传递的消息。请忽略其中的 mongo 部分,因为它还没有发挥任何作用。
我也想知道我的 AMQP 方法及其用法是否正确
<script>
$(document).ready(function(){
var username = '<%= @user.email %>';
var roomname = 'Bazingaa';
socket = new WebSocket('ws://127.0.0.1:8080/');
socket.onopen = function(msg){
console.log('connected');
socket.send(JSON.stringify({status:'status', username:username, roomname:roomname}));
}
socket.onmessage = function(msg){
$('#chat-log').append(msg.data);
}
});
</script>
<div class='block'>
<div class='content'>
<h2 class='title'><%= @room.name %></h2>
<div class='inner'>
<div id="chat-log">
</div>
<div id="chat-console">
<textarea rows="5" cols="40"></textarea>
</div>
</div>
</div>
</div>
<style>
#chat-log{
color:#000;
font-weight:bold;
margin-top:1em;
width:900px;
overflow:auto;
height:300px;
}
#chat-console{
bottom:10px;
}
textarea{
width:100%;
height:60px;
}
</style>
【问题讨论】:
-
如果我将 amqp 代码作为守护进程运行,有人能告诉我如何在生产环境中组织我的代码吗?任何可以帮助我组织代码的示例代码都会有很大帮助。