【发布时间】:2017-01-26 04:54:08
【问题描述】:
在下面的代码中,我如何显示矩形和三角形的区域。目前我只能打印字符串,但会返回该区域。那么如何打印函数的返回值。我应该在代码中更改什么,请帮助。
class Shape {
protected:
int width, height;
public:
Shape( int a = 0, int b = 0) {
width = a;
height = b;
}
virtual int area() {
cout << "Parent class area :" <<endl;
return 0;
}
};
class Rectangle: public Shape {
public:
Rectangle( int a = 0, int b = 0):Shape(a, b) { }
int area () {
cout << "Rectangle class area :" <<endl;
return (width * height);
}
};
class Triangle: public Shape{
public:
Triangle( int a = 0, int b = 0):Shape(a, b) { }
int area () {
cout << "Triangle class area :" <<endl;
return (width * height / 2);
}
};
// Main function for the program
int main( ) {
Shape *shape;
Rectangle rec(10,7);
Triangle tri(10,5);
// store the address of Rectangle
shape = &rec;
// call rectangle area.
shape->area();
// store the address of Triangle
shape = &tri;
// call triangle area.
shape->area();
return 0;
}
【问题讨论】:
-
您没有打印出任何结果。您只是将它们归还,而不是将它们分配给任何东西,因此它们会丢失。
-
没错。在方法
area中打印字符串通常是个坏主意。你想要的大概是std::cout << shape->area() << std::endl;。
标签: c++ polymorphism virtual-functions