选择 UIPickerView 项目时运行 ibaction答案

【问题标题】：Run ibaction when UIPickerView item is selected选择 UIPickerView 项目时运行 ibaction
【发布时间】：2012-10-17 10:35:02
【问题描述】：

我正在使用 Xcode 4，但我的选择器视图存在一些问题。当 UIPickerView 的选定对象等于“European Sights”时，我不想转到其他视图

这是我要运行的操作：

-(IBAction)switchviewMainToQuiz:(id)sender {


    if([arrayPickerView objectAtIndex:1] == @"European Sights"){

        ViewControllerQuiz *quizView = [[ViewControllerQuiz alloc] initWithNibName:nil bundle:nil];

        [self presentModalViewController:quizView animated:YES];

    }
    else{
        lblPickerView.text = @"werkt niet";
    }
}

这是剩下的代码（pickerview 代码）：

- (void)viewDidLoad
{
    [super viewDidLoad];

    // Do any additional setup after loading the view, typically from a nib.

    //Put strings in the PickerView and show in label what's selected
    arrayPickerView = [[NSMutableArray alloc] init];
    [arrayPickerView addObject:@"European Sights"];
    [arrayPickerView addObject:@"Flags of the world"];
    [arrayPickerView addObject:@"Something2"];
    [arrayPickerView addObject:@"Something3"];
    [arrayPickerView addObject:@"Something4"];

    [pickerView selectRow:1 inComponent:0 animated:NO];
    lblPickerView.text= [arrayPickerView objectAtIndex:[pickerView selectedRowInComponent:0]];


}

- (NSInteger)numberOfComponentsInPickerView:(UIPickerView *)pickerView;
{
    return 1;
}

- (void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component
{
    lblPickerView.text=    [arrayPickerView objectAtIndex:row];
}

- (NSInteger)pickerView:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component;
{
    return [arrayPickerView count];
}

- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component;
{
    return [arrayPickerView objectAtIndex:row];


}

UIPickerView 工作并在标签中显示所选项目。有人可以帮我吗？谢谢你

【问题讨论】：

标签： iphone objective-c ios xcode cocoa

【解决方案1】：

objectAtIndex:0

obj c 使用从零开始的数组

【讨论】：

您能否将其添加到代码中，因为我没有完成它，因为我是 ios 编程新手。
if([arrayPickerView objectAtIndex:0] == @"European Sights"){

【解决方案2】：

- (void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component
{
    lblPickerView.text=    [arrayPickerView objectAtIndex:row];

    UIButton *sender = [UIButton buttonWithType:UIButtonTypeCustom]; 
    sender.tag = row;
    [self  switchviewMainToQuiz:(id)sender];  // send a dummy button as the action is conformed for an UIButton interception
}

【讨论】：

【解决方案3】：

试试这行代码：

- (void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component { lblPickerView.text= [arrayPickerView objectAtIndex:row]; if(lblPickerView.text isEqualToString:@"European Sights"){ ViewControllerQuiz *quizView = [[ViewControllerQuiz alloc] initWithNibName:nil bundle:nil]; [自我presentModalViewController：quizView动画：YES]； } 别的{ lblPickerView.text = @"werkt niet"; } }

【讨论】：