【发布时间】:2016-02-21 04:44:33
【问题描述】:
Lorem Ipsum 只是印刷和排版行业的虚拟文本。自 1500 年代以来,Lorem Ipsum 一直是行业的标准虚拟文本,当时一位不知名的印刷商采用了一种类型的厨房并将其加扰以制作类型样本书。它不仅经历了五个世纪,而且经历了电子排版的飞跃,基本保持不变。它在 1960 年代随着包含 Lorem Ipsum 段落的 Letraset 表的发布而流行起来,最近还随着 Aldus PageMaker 等桌面出版软件(包括 Lorem Ipsum 的版本)而普及。
//pagination function
public function pagination($per_page = 10, $page = 1, $url = '', $total){
$adjacents = "2";
$page = ($page == 0 ? 1 : $page);
$start = ($page - 1) * $per_page;
$prev = $page - 1;
$next = $page + 1;
$lastpage = ceil($total/$per_page);
$lpm1 = $lastpage - 1;
$pagination = "";
if($lastpage > 1)
{
$pagination .= "<li class='details'>Page $page of $lastpage</li>";
if ($lastpage < 7 + ($adjacents * 2))
{
for ($counter = 1; $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<li class='active' ><a >$counter</a></li>";
else
$pagination.= "<li><a href='{$url}$counter'>$counter</a></li>";
}
}
elseif($lastpage > 5 + ($adjacents * 2))
{
if($page < 1 + ($adjacents * 2))
{
for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
{
if ($counter == $page)
$pagination.= "<li class='active'><a >$counter</a></li>";
else
$pagination.= "<li><a href='{$url}$counter'>$counter</a></li>";
}
$pagination.= "<li class='dot'>...</li>";
$pagination.= "<li><a href='{$url}$lpm1'>$lpm1</a></li>";
$pagination.= "<li><a href='{$url}$lastpage'>$lastpage</a></li>";
}
elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
{
$pagination.= "<li><a href='{$url}1'>1</a></li>";
$pagination.= "<li><a href='{$url}2'>2</a></li>";
$pagination.= "<li class='dot'>...</li>";
for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
{
if ($counter == $page)
$pagination.= "<li class='active'><a >$counter</a></li>";
else
$pagination.= "<li><a href='{$url}$counter'>$counter</a></li>";
}
$pagination.= "<li class='dot'>..</li>";
$pagination.= "<li><a href='{$url}$lpm1'>$lpm1</a></li>";
$pagination.= "<li><a href='{$url}$lastpage'>$lastpage</a></li>";
}
else
{
$pagination.= "<li><a href='{$url}1'>1</a></li>";
$pagination.= "<li><a href='{$url}2'>2</a></li>";
$pagination.= "<li class='dot'>..</li>";
for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<li class='active'><a >$counter</a></li>";
else
$pagination.= "<li><a href='{$url}$counter'>$counter</a></li>";
}
}
}
if ($page < $counter - 1){
$pagination.= "<li><a href='{$url}$next'>Next</a></li>";
// $pagination.= "<li><a href='{$url}$lastpage'>Last</a></li>";
}else{
//$pagination.= "<li><a class='current'>Next</a></li>";
// $pagination.= "<li><a class='current'>Last</a></li>";
}
}
return $pagination;
}
public function Recipe_list()
{
$jpag= new Customer_Recipes;
/*------------------------------pagination------------------------------*/
$page=1;
$limit=15;
$start=0;
if(isset($_GET['page']) && $_GET['page']!='')
{
$page=$_GET['page'];
}
$start=($page-1)*$limit;
$rows = $customermodel->count_recipes($Cat,$Sub,$uid);
if($rows>0)
$jb = $customermodel->get_recipes($Cat,$Sub,$uid,$start,$limit);
}
?>
<div class="row">
<div class="md-12"> <ul class="pagination">
<?php
echo $jpag->pagination($limit,$page,URL."Customer_Recipes/Recipe_list/?Cat=$Cat&Sub=$Sub&uid=$uid&page=",$rows);
?>
</ul>
</div>
</div>
【问题讨论】:
-
检查swf文件的路径
-
它是正确的,如果我给出它加载的相同位置的图像路径
-
把绝对路径写成这样xyz.com/swf/0.swf
-
尝试 www.urdomain.com/swf/0.swf 并检查它显示的内容
-
将路径更改为 .urdomain.com/swf/0.swf 但没有结果