将 NSArray 转换为 NSString 包含 NSDictionary

Question

我正在尝试将 NSArray 转换为包含 NSDictionary 的 NSString ，我可以通过数组迭代和最后一个附加字符串来实现这一点，但我认为应该有一些简单的方法来实现这一点比如componentsJoinedByString:有没有？

我的一个示例数组是，

[o] {name="ABC", age = "19", package = "3.4"}

[1] {name="PQR", age = "33", package = "5.0"}

[2] {name="XYZ", age = "24", package = "2.2"}

我现在正在做的是，

NSString *name = @"";
NSString *age = @"";
NSString *package = @"";
                 
for(NSDictionary *p in array)
{
    name = [name stringByAppendingFormat:@"%@,",[p valueForKey:@"name"]];

    age = [age stringByAppendingFormat:@"%@,",[p valueForKey:@"age"]];

    package = [package stringByAppendingFormat:@"%@,",[p valueForKey:@"package"]];
}
                 
name = [name substringToIndex:[name length] - 1];
age = [age substringToIndex:[age length] - 1];
package = [package substringToIndex:[package length] - 1];
                 
NSLog(@"%@",name);
NSLog(@"%@",age);
NSLog(@"%@",package);

有没有更简单的方法来获得这个？

Answer 1

简单地做：

假设你有 array 包含 NSDictionary 的对象。

NSString *name = [[array  valueForKey:@"name"] componentsJoinedByString:@","];
NSString *age = [[array  valueForKey:@"age"] componentsJoinedByString:@","];
NSString *package = [[array  valueForKey:@"package"] componentsJoinedByString:@","];

NSLog(@"%@",name);
NSLog(@"%@",age);
NSLog(@"%@",package);