赋予所有这些可选值

Question

您好，我有变量，但给了所有变量Optional()。我如何在下面解决我的代码。

下面你可以看到koltuklarkoltuklaridler数组的Json附加代码

        for name in json as! [AnyObject] {

            let SeatName = name["SeatName"]
            let SeatDesignId = name["SeatDesignId"]
            self.koltuklar.append("\(SeatName)*\(SeatDesignId)*")

            if let blogs = json["SeatDetail"] as? [[String: AnyObject]] {
                for blog in blogs {

                    let TicketTypeId = blog["TicketTypeId"]
                    let TicketTypeName = blog["TicketTypeName"]
                    let Amount = blog["Amount"]

                    self.koltuklaridler.append("\(SeatDesignId)*\(TicketTypeId)*\(TicketTypeName)*\(Amount)*")


                }

            }

在下面您可以看到代码中的 tableview（该代码在 koltuklaridler 内部搜索 id 后打开 koltuklar 索引路径项，当找到时从中获取一些变量）

var koltuklar = [""]
var koltuklaridler = [""]

if let myStrings:String! = koltuklar[indexPath.row]{

    print("\(myStrings!)")

    let myStringArrf = myStrings.componentsSeparatedByString("*")


    print("\(myStringArrf)")


    if let koltukisims:String! = String(myStringArrf[0]) {

        cell.koltukName.text = koltukisims
    }


    print(" STR - \(myStringArrf[1] as String!)")


    if let index = koltuklaridler.indexOf(myStringArrf[1] as String!) {

        let myStringdetaysecilen = koltuklaridler[index]

        print("myStringdetaysecilen \(myStringdetaysecilen)")


    }

也是我的json文件

[
    {
        "SeatDesignId": 16484,
        "SeatName": "A6",
        "SaloonId": 148,
        "SeatDetail": [
            {
                "TicketTypeId": 1,
                "TicketTypeName": "Okay",
                "Amount": 13
            }
        ]
    },

输出

Optional("A17")*Optional(16254)*
["Optional(\"A17\")", "Optional(16254)", ""]
STR - Optional(16254)

所有变量输出可选我尝试了所有方法但没有修复。

Answer 1

正如我在 cmets 中提到的，无论何时使用字符串插值"\(...)"，请确保所有可选字符串都已解包。从字典中读取的值始终是可选的。

此代码解开所有可选字符串

for name in json as! [[String:AnyObject]] {

  guard let SeatName = name["SeatName"] as? String,
        SeatDesignId = name["SeatDesignId"] as? Int else  {
      continue
  }
  self.koltuklar.append("\(SeatName)*\(SeatDesignId)*")

  if let blogs = json["SeatDetail"] as? [[String: AnyObject]] {
    for blog in blogs {
      if let TicketTypeId = blog["TicketTypeId"] as? Int,
           TicketTypeName = blog["TicketTypeName"]  as? String,
                   Amount = blog["Amount"]  as? Int {
        self.koltuklaridler.append("\(SeatDesignId)*\(TicketTypeId)*\(TicketTypeName)*\(Amount)*")        
      }
    }
}

编辑：我根据 JSON 将转换更新为实际类型

现在将两个数组都声明为空字符串数组。

var koltuklar = [String]()
var koltuklaridler = [String]()

并删除第一行中的可选绑定

let myStrings = koltuklar[indexPath.row]
print("\(myStrings)")
...

顺便说一句：您用星号“序列化”字符串并在表格视图中对其进行反序列化的方式非常非常笨拙且效率低下。为数据记录使用自定义类或结构。

Answer 2

您的问题是您正在从没有 if let 语句的 dict 值创建字符串，因此它返回一个可选值：

对于 json 中的名称为！ [任何对象] {

        if let SeatName = name["SeatName"],
           let SeatDesignId = name["SeatDesignId"] {
            self.koltuklar.append("\(SeatName)*\(SeatDesignId)*")
        }

        if let blogs = json["SeatDetail"] as? [[String: AnyObject]] {
            for blog in blogs {

                if let TicketTypeId = blog["TicketTypeId"],
                   let TicketTypeName = blog["TicketTypeName"],
                   let Amount = blog["Amount"] {
                   self.koltuklaridler.append("\(SeatDesignId)*\(TicketTypeId)*\(TicketTypeName)*\(Amount)*")
                }
            }

        }

Answer 3

有两种操作方式可选。

1. 使用“！”展开但如果 value 为 nil，则有可能发生崩溃。
2. 使用“if let”条件使用术语调用“可选绑定”展开。

if let var = "assigned your optional variable"{
print(var)
}

您将获得没有可选的变量。