将 XML 存储解析为 NSArray

Question

我正在尝试解析 XML 并将 XML 的一个元素中的 URL 存储到 NSArray 中。到目前为止，这是我的代码：

 NSURL *url = [NSURL URLWithString:@"http://www.316apps.com/LakesideDocs/podcasttrial.xml"];

   NSData *xmlData = [[NSMutableData alloc] initWithContentsOfURL:url];
   NSError *error;
   GDataXMLDocument *doc = [[GDataXMLDocument alloc] initWithData:xmlData 
                                                          options:0 error:&error];

   NSArray *channels = [doc.rootElement elementsForName:@"channel"];
   for (GDataXMLElement *channel in channels) {            


       NSArray *items = [channel elementsForName:@"item"];
       for (GDataXMLElement *item in items) {

           NSString *articlePoint = [item valueForChild:@"link"];
           NSArray *linkarray = [[NSArray alloc] initWithObjects:articlePoint, nil];

           NSLog(@"%@", linkarray);

       }

   }

对于我期望的 NSLog：

TabBarSample[40191:fb03] (
    (
    "http://domain.com/image1.jpg"
 ),
(
"http://domain.com/image2.jpg"
)
)

但我明白了：

TabBarSample[40191:fb03] (
"http://domain.com/image1.jpg"
)
TabBarSample[40191:fb03] (
"http://domain.com/image2.jpg"
)

我做错了什么？

Answer 1

每次循环都会创建一个新数组：

 NSArray *linkarray = [[NSArray alloc] initWithObjects:articlePoint, nil];

相反，您希望在 llop 之外使用 NSMutableArray 并在每个循环期间添加一个对象

   NSMutableArray *linkarray = [NSMutableArray array];
   NSArray *items = [channel elementsForName:@"item"];
   for (GDataXMLElement *item in items) {

       NSString *articlePoint = [item valueForChild:@"link"];
       [linkarray addObject:articlePoint];

       NSLog(@"%@", linkarray);

   }

如果增加的数组让你感到困惑，你应该把 NSLog 放在 for 循环之后：

   NSMutableArray *linkarray = [NSMutableArray array];
   NSArray *items = [channel elementsForName:@"item"];
   for (GDataXMLElement *item in items) {

       NSString *articlePoint = [item valueForChild:@"link"];
       [linkarray addObject:articlePoint];
   }

   NSLog(@"%@", linkarray);
   NSLog(@"count: %d", [linkarray count]);