paymentWithProductIdentifier 的替代解决方案是什么？答案

【问题标题】：what is the alternative solution for paymentWithProductIdentifier?paymentWithProductIdentifier 的替代解决方案是什么？
【发布时间】：2012-06-01 09:58:50
【问题描述】：

您好，我在我的项目中使用 APP 购买。当我运行这个项目时，一切正常，除了我收到一条警告消息说“paymentWithProductIdentifier 已被弃用”，我经历了堆栈溢出中提出的类似问题，但我不满意。我向您展示了我在下面的项目中使用的编码

SKPayment *payment=[SKPayment paymentWithProductIdentifier:@"com.mycompany.dmaker.maker1"];
[[SKPaymentQueue defaultQueue] addTransactionObserver:self];
[[SKPaymentQueue defaultQueue] addPayment:payment];

谁能告诉我 1）此警告的替代方法。 2）如果我使用这个现有代码，或者告诉我这个项目是否在应用商店中获得批准。

【问题讨论】：

标签： iphone objective-c xcode in-app-purchase

【解决方案1】：

试试这个：

SKProduct *selectedProduct = <#from the products response list#>;
SKPayment *payment = [SKPayment paymentWithProduct:selectedProduct];
[[SKPaymentQueue defaultQueue] addPayment:payment];

【讨论】：

你能告诉我这行“”的示例代码
这只是用户选择购买的产品之一，您在调用后得到 - (void)productsRequest:(SKProductsRequest *)request didReceiveResponse:(SKProductsResponse *)response。
回答surendher获取示例代码。这进入了 didReceiveResponse 委托： SKProduct * selectedProduct = nil; selectedProduct = [response.products objectAtIndex:0];

【解决方案2】：

您可以将paymentWithProductIdentifier:替换为以下代码：

// SKPayment *payment = [SKPayment paymentWithProductIdentifier:productId];
// [[SKPaymentQueue defaultQueue] addPayment:payment];
NSSet *productIdentifiers = [NSSet setWithObject:productId];
self.productsRequest = [[SKProductsRequest alloc] initWithProductIdentifiers:productIdentifiers];
self.productsRequest.delegate = self; // your wrapper for IAP or AppDelegate or anything
[self.productsRequest start];

而productsRequest 是一个保留属性。

并实现一个 SKProductsRequestDelegate 方法：

- (void)productsRequest:(SKProductsRequest *)request didReceiveResponse:(SKProductsResponse *)response
{
    for (SKProduct *product in response.products) {
        SKPayment *payment = [SKPayment paymentWithProduct:product];
        [[SKPaymentQueue defaultQueue] addPayment:payment];
    }
    self.productsRequest = nil;
}

【讨论】：

【解决方案3】：

您有 3 个选项：

用预处理器定义抑制这个警告：

#pragma clang diagnostic push
#pragma clang diagnostic ignored "-Wdeprecated-declarations"
SKPayment *payment=[SKPayment paymentWithProductIdentifier:@"com.mycompany.dmaker.maker1"];
#pragma clang diagnostic pop
[[SKPaymentQueue defaultQueue] addPayment:payment];

创建SKMutablePayment 而不是SKPayment：

SKMutablePayment *payment = [[SKMutablePayment alloc] init];
payment.productIdentifier = @"com.mycompany.dmaker.maker1";
payment.quantity = 1;
[[SKPaymentQueue defaultQueue] addPayment:payment];

使用paymentWithProduct:便捷初始化器：

SKPayment *payment = [SKPayment paymentWithProduct:<# product that you received in productsRequest:didReceiveResponse: #>];
[[SKPaymentQueue defaultQueue] addPayment:payment];

【讨论】：

【解决方案4】：

您可以改用以下代码，它确实有一些您可能已经拥有的额外代码，但只是为了确保

#define kInAppPurchaseId "(your product ID here)"

- (void)makePurchase{
//call this when you would like to begin the purchase
//like when the user taps the "purchase" button
NSLog(@"User requests to make purchase");

if([SKPaymentQueue canMakePayments]){
    NSLog(@"User can make payments");

    SKProductsRequest *productsRequest = [[SKProductsRequest alloc] initWithProductIdentifiers:[NSSet setWithObject:kInAppPurchaseId]];
    productsRequest.delegate = self;
    [productsRequest start];

}
else{
    //the user is not allowed to make payments
    NSLog(@"User cannot make payments due to parental controls");
}
}

- (void)productsRequest:(SKProductsRequest *)request didReceiveResponse:(SKProductsResponse *)response{
SKProduct *validProduct = nil;
int count = [response.products count];
if(count > 0){
    validProduct = [response.products objectAtIndex:0];
    NSLog(@"Products Available!");
    [self purchase:validProduct];
}
else if(!validProduct){
    NSLog(@"No products available");
}
}

- (IBAction)purchase:(SKProduct *)product{
SKPayment *payment = [SKPayment paymentWithProduct:product];
[[SKPaymentQueue defaultQueue] addTransactionObserver:self];
[[SKPaymentQueue defaultQueue] addPayment:payment];
}

我在我的一个应用程序中使用此代码，所以它应该可以工作。

【讨论】：

你的帖子不适合这个问题。问题是，paymentWithProductIdentifier 在 iOS 5.0 中已被弃用。一切正常，但仍然有警告消息。