【发布时间】:2016-01-12 17:33:40
【问题描述】:
当我尝试使用 PHP 服务器注册我的用户表单 iOS 时,总是在 mysql db 中添加空行。
当我从 php 打印变量值时,它是空的。
这是我的代码
-(void)sendLogininfoToServer{
NSUserDefaults *login = [NSUserDefaults standardUserDefaults];
NSString *name=[login stringForKey:@"name"];
//NSString *image=[login stringForKey:@"image"];
NSString *email=[login stringForKey:@"email"];
serverConnection=[[serverRequestProtocol alloc]init];
serverConnection.delegate=self;
//NSLog(@"get doc list%@",stringValue);
NSString *url=@"http://example.in/php/signup.php";
NSString *post = [NSString stringWithFormat:@"fname=%@&email=%@&country=%@&city=%@",name,email,@"India",@"Bangalore"];
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSMutableURLRequest *request =[[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString: url]];
NSString *serverOutput=[serverConnection getData:request :@"POST":postData];
NSLog(@"%@",serverOutput);
}
-(NSString *)getData:(NSMutableURLRequest *)request:(NSString *)requestType:(NSData *)data{
[request setHTTPMethod:requestType];
NSInteger millisecondsFromGMT = 1000 * [[NSTimeZone localTimeZone] secondsFromGMT];
NSString *str1=[NSString stringWithFormat:@"%ld",millisecondsFromGMT];
[request setHTTPBody:data];
[request setValue:@"application/json; charset=UTF-8" forHTTPHeaderField:@"Content-Type"];
[request setValue:@"iphone" forHTTPHeaderField:@"X-User-agent"];
[request setValue:str1 forHTTPHeaderField:@"X-TimeZoneOffset"];
NSURLResponse *response;
NSError *err;
NSData *returnData = [NSURLConnection sendSynchronousRequest: request returningResponse:&response error:&err];
NSString * serverOutput= [[NSString alloc]initWithData:returnData encoding:NSASCIIStringEncoding];
return serverOutput;
}
我从 php 结果中获得了成功,但总是空值是 addin ginto db。
我的 php 代码
<?php
header("Content-type: text/html; charset=utf-8");
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "dbname";
$charset="UTF8";
$name=$_POST['fname'];
$email=$_POST['email'];
$country=$_POST['country'];
$city=$_POST['city'];
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
/* change character set to utf8 */
if (!mysqli_set_charset($conn, "utf8")) {
printf("Error loading character set utf8: %s\n", mysqli_error($conn));
exit();
} else {
mysqli_close($link);$sql = "INSERT INTO `basicinfo`(`fname`, `email`,`country`, `city`) VALUES ('$name','$email','$country','$city')";
if ($conn->query($sql) === TRUE) {
echo $name;
} else {
echo "fail";
}
}
exit;
?>
请帮帮我
【问题讨论】:
-
顺便说一下,
getData方法声明不符合标准方法签名。你应该做- (NSString *)getDataWithRequest:(NSMutableURLRequest *)request requestType:(NSString *)requestType data:(NSData *)data。然后将其称为[serverConnection getDataWithRequest:request requestType:@"POST" data:postData]。 -
我在下面更新了我的答案
-
您在上面将
Content-Type设置为application/json这是不正确的。下面,你根本不设置它。您可能希望将其设置为application/x-www-form-urlencoded。不需要设置Content-Type,但这是一种很好的做法。 -
哦,好的,会更正那个..谢谢
-
很抱歉用 cmets 来攻击你,但你也想在使用 SQL 中的值之前调用
mysqli_real_escape_string。如果你不这样做,你就会面临 SQL 注入攻击。坦率地说,它看起来甚至不像 performing the query,所以也许你应该先解决这个问题,但请确保在执行 SQL 之前转义这些值。
标签: php ios mysql objective-c post