无法从 NSDictionary iOS 获取所有匹配字符串

Question

我是 iOS 新手，逻辑有点弱。

谁能帮帮我，

我想从 NSDictionary 中获取所有匹配的数据。

例如：

我的tempDict 是包含这个的 NSDictionary，

临时字典：

errorCode = 00;
errorMessage = "<null>";
pastConsultations =     (

            {
        date = "16 December 2016";
        day = Friday;
        doctorName = "<null>";
        localTime = "07:30 AM";
        symptoms = q;
        today = Yes;
    },
            {
        date = "16 December 2016";
        day = Friday;
        doctorName = "<null>";
        localTime = "07:30 AM";
        symptoms = g;
        today = Yes;
    },
            {
        date = "13 December 2016";
        day = Tuesday;
        doctorName = "<null>";
        localTime = "12:30 PM";
        symptoms = fever;
        today = No;
    }
);
upcomingConsultations =     (
            {
        date = "16 December 2016";
        day = Friday;
        localTime = "09:30 PM";
        symptoms = "";
        today = Yes;
    },
            {
        date = "16 December 2016";
        day = Friday;
        localTime = "09:30 PM";
        symptoms = chj;
        today = Yes;
    },
            {
        date = "18 December 2016";
        day = Sunday;
        localTime = "12:30 PM";
        symptoms = "test an incoming ";
        today = No;
    }
);
}

在pastConsultations 键中，我想获取所有包含AM 的嵌套数据

即我的输出应该是：

{ //Array at 0th index
            date = "16 December 2016";
            day = Friday;
            doctorName = "<null>";
            localTime = "07:30 AM";
            symptoms = q;
            today = Yes;
        },
                { //Array at 1st index
            date = "16 December 2016";
            day = Friday;
            doctorName = "<null>";
            localTime = "07:30 AM";
            symptoms = g;
            today = Yes;
        }
}

这是我尝试过的代码，但它不起作用，请帮助我在哪里出错？

NSArray *allKeys;
        for (int i=0; i<[tempDict count]; i++) {
           allKeys = [[[tempDict valueForKey:@"upcomingConsultations"] objectAtIndex:i] allKeys];



            NSString *targetKey = nil;
            // NSArray *allKeys = [[tempDict valueForKeyPath:@"pastConsultations"] allKeys];
            for (int j = 0; j < [allKeys count]; ++j) {
                NSString *key = [allKeys objectAtIndex:i];
                NSString *obj = [[[tempDict valueForKey:@"upcomingConsultations"] objectAtIndex:i] objectForKey:key];
                if ([obj rangeOfString:searchText].location != NSNotFound) { // searchedString is what you're looking for
                    targetKey = key;
                    NSLog(@"found match");
                    break;
                }
            }
        }

Answer 1

试试这个代码：

假设您已经加载了 tempDict 字典。

NSMutableArray *morningPastArr = [[NSMutableArray alloc] init];

NSArray *pastArray = [tempDict objectForKey:@"pastConsultations"];
for (int i=0;i<[pastArray count]; i++) {
  NSDictionary *eachPast = [pastArray objectAtIndex:i];
  NSString *time = [eachPast objectForKey:@"localTime"];
  if (![time rangeOfString:@"AM"].location == NSNotFound) {
    [morningPastArr addObject:eachPast];
  }
}

// finally you will have like what you need in morningPastArr.

编辑： 如果您想组合搜索结果，例如 AM 条目和 Friday only 的结果，您可以这样做：

NSMutableArray *morningAndFridayPastArr = [[NSMutableArray alloc] init];

NSArray *pastArray = [tempDict objectForKey:@"pastConsultations"];
for (int i=0;i<[pastArray count]; i++) {
  NSDictionary *eachPast = [pastArray objectAtIndex:i];
  NSString *time = [eachPast objectForKey:@"localTime"];
  NSString *day = [eachPast objectForKey:@"day"];
  if ((![time rangeOfString:@"AM"].location == NSNotFound)&&([day isEqualToString:@"Friday"])) {
    [morningAndFridayPastArr addObject:eachPast];
  }
}

Answer 2

您可以使用NSPredicate，如下所示：

NSPredicate *predicate;
NSMutableArray *filteredData=[[NSMutableArray alloc]init];

predicate = [NSPredicate predicateWithFormat:@"localTime contains[c] %@",@"AM"];
//OR Use below predicate as suggested by Rishi
predicate = [NSPredicate predicateWithFormat:@"localTime ENDSWITH 'AM'"];

filteredData=[[[tempDict valueForKey:@"pastConsultations"] filteredArrayUsingPredicate:predicate]] mutableCopy];

希望这会有所帮助。