MouseHandler 事件和委托 c#

Question

过去几天我一直在研究事件和委托，我决定尝试使用这两者创建一个 MouseHandler 类。

基本上我有这个问题，鼠标点击没有注册，x 和 y 轴的位置返回为 0，不注册我只是意味着通过 console.WriteLine() 在输出控制台中显示。我已经研究了一段时间，但我没有运气，所以我想知道你们中是否有人能指出我正确的方向，不胜感激。

提前谢谢你。

MouseHandler.cs

class MouseHandler
    {

        public delegate void MouseEventHandler(object source, MouseEventHandlerArgs 

        public event MouseEventHandler MouseLeftClick;
        public event MouseEventHandler MouseRightClick;
        public event MouseEventHandler MouseMoved;

        public MouseState mouseState = Mouse.GetState();

        protected virtual void OnMouseLeftClick(MouseState m)
        {
            mouseState = m;
            if(MouseLeftClick != null)
            {
               MouseLeftClick(this, new MouseEventHandlerArgs() { MouseButtonPress = m });

            }
        }

        protected virtual void OnMouseMoved(MouseState m)
        {
            if (MouseMoved != null)
            {

                MouseMoved(this, new MouseEventHandlerArgs(){MouseButtonPress = m  });
               Console.WriteLine(mouseState.Position.X);
            }
        }

        public void Update(GameTime gt)
        {
            OnMouseLeftClick(mouseState);
            OnMouseMoved(mouseState);
        }
    }

MouseEventHandlerArgs

class MouseEventHandlerArgs : EventArgs
{
    public MouseState MouseButtonPress { get; set; }


}

鼠标测试

class MouseTest
    {
        public void OnMouseLeftClick(object source, MouseEventHandlerArgs e)
        {
            Console.WriteLine("Mouse Left click" + e.MouseButtonPress.LeftButton);
        }        

        public void OnMouseMoved(object source, MouseEventHandlerArgs e)
        {
            Console.WriteLine("you moved mouse to x " + e.MouseButtonPress.Position.X + " Y pos " + e.MouseButtonPress.Position.Y );
        }
    }

游戏 1 在更新方法内：

mouseHandler.MouseLeftClick += mouseTest.OnMouseLeftClick;
mouseHandler.MouseMoved += mouseTest.OnMouseMoved;
//mouseHandler.Update(gameTime);

Answer 1

几个问题：

1) 看起来您在检查按钮是否被点击或鼠标是否被移动之前触发了事件。

2) 当类被实例化时，您只会获得一次鼠标状态。您需要在 Update() 方法中调用 Mouse.GetState()。

// New class fields
private ButtonState _previousButtonState = ButtonState.Released;
private int _previousMouseX;
private int _previousMouseY;

// New Update() method
public void Update(GameTime gt)
{
    MouseState mouseState = Mouse.GetState();

    // Check if the left button was clicked (pressed now, but not last Update())
    if (mouseState.LeftButton == ButtonState.Pressed && _previousButtonState != ButtonState.Pressed)
        OnMouseLeftClick(mouseState);

    _previousButtonState = mouseState.LeftButton;

    // See if the mouse has moved since the last Update()
    if (mouseState.X != _previousMouseX || mouseState.Y != _previousMouseY)
    {
        OnMouseMoved(mouseState);
        _previousMouseX = mouseState.X;
        _previousMouseY = mouseState.Y;
    }   
}