使用换行符解析字符串然后分配给变量

Question

我正在尝试将串行输入解析为句子，然后将这些句子分配给一个变量。这是我正在尝试做的一个例子。我的串口目前输出这个：

This is the first sentence. 
This is the second sentence. 
This is the third sentence. 

我阅读并使用以下方法打印：

scanner := bufio.NewScanner(port)
    for scanner.Scan() {
        fmt.Println(scanner.Text())
        }

我想做的是将每个句子分配给一个新变量。我想稍后做这样的事情（示例）：

fmt.Printf("First sentence: %q\n", firstSen)
fmt.Printf("Second sentence: %q\n", secondSen)
fmt.Printf("Third sentence: %q\n", thirdSen)

它应该输出：

First sentence: This is the first sentence. 
Second sentence: This is the second sentence. 
Third sentence: This is the third sentence.

我该怎么做呢？谢谢。

Answer 1

从输入中收集行：

var lines []string
scanner := bufio.NewScanner(port)
for scanner.Scan() {
    lines = append(lines, scanner.Text())
}
if err := scanner.Err(); err != nil {
    // handle error
}

循环遍历变量，为变量分配一行：

var firstSen, secondSen, thirdSen string
for i, s := range []*string{&firstSen, &secondSen, &thirdSen} {
    if i >= len(lines) {
        break
    }
    *s = lines[i]
}

如题所示打印：

fmt.Printf("First sentence: %q\n", firstSen)
fmt.Printf("Second sentence: %q\n", secondSen)
fmt.Printf("Third sentence: %q\n", thirdSen)

根据您的要求，您可以删除变量并直接使用行切片：

fmt.Printf("First sentence: %q\n", line[0])
fmt.Printf("Second sentence: %q\n", line[1])
fmt.Printf("Third sentence: %q\n", line[2])