使用 setVisible() 的 Java GUI

Question

我有一个像这样从 JFrame 扩展的类：

public class TicTacToeSubMenu extends JFrame implements ActionListener { }

在同一个文件中，我有另一个用于客户端连接的类，如下所示：

class ListenThread extends Thread { }

问题是在 ListenThread 类中，我试图退出当前帧并打开一个新帧，到目前为止，新帧按需要打开，但当前帧不会退出。

我使用了这两个命令，但都没有工作：

1. TicTacToeSubMenu.this.setVisible(false);

2. setVisible(false);

如何从同一文件的另一个类中退出当前帧？

一个更大的例子：

从以前的寡妇框架我这样做：

            TicTacToeSubMenu win = new TicTacToeSubMenu(word, false);
            win.setTitle("Tic Tac Toe");
            win.pack();
            win.setLocation(600, 200);
            setVisible(false);
            win.show();

然后在一个新文件和新框架中：

public class TicTacToeSubMenu extends JFrame implements ActionListener {
    variables.....

public TicTacToeSubMenu(String username, boolean playing) {
    new TicTacToeSubMenu();
}


public TicTacToeSubMenu() {
    connectUser();
}

public void connectUser() {
    clientThread = new ConnectThread();
    clientThread.start();

}

class ConnectThread extends Thread {
    InputStream input;
    OutputStream output;
    ObjectOutputStream oos;
    Socket s;

    public void sendText(String text) {
        try {
            oos.writeObject(text);

        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }

    public void run() {
        try {
            s = new Socket(HOST, PORT);
            output = s.getOutputStream();
            oos = new ObjectOutputStream(output);

            isOnline = true;
            isConnected = true;

            new ListenThread(s).start();

        } catch (UnknownHostException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }
}

class ListenThread extends Thread {

    Socket s;
    InputStream input;
    ObjectInputStream ois;

    public ListenThread(Socket s) {
        this.s = s;
        try {
            input = s.getInputStream();
            ois = new ObjectInputStream(input);
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

    }

    public void run() {
        while (isConnected) {
            try {
                final String inputMessage = (String) ois.readObject();
                System.out.println(inputMessage);
                String user;
                user = getWord(inputMessage, 0);
                String opponent;
                opponent = getWord(inputMessage, 1);
                String message = getWord(inputMessage, 2);


                if (!user.equalsIgnoreCase(un)
                        && opponent.equalsIgnoreCase(un)
                        {

                            TicTacToeMultiPlayer window = new TicTacToeMultiPlayer(
                                    un, user, t2, playing, turn);
                            window.setTitle("Tic Tac Toe");
                            window.setLocation(400, 100);
                            window.pack();
                            TicTacToeSubMenu.this.setVisible(false);
                            window.show();
                        }
            } catch (Exception e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

        }
    }
}

}

Answer 1

如果您想“隐藏”一个 JPanel，请使用代码“this.dispose();”而不是将可见性设置为 false。