Zendframework 联盟问题

Question

我正在运行这段代码

$sq = $this->_codes->getAdapter()->select()
            ->from (array('cs' => 'code_statuses'), array('total' =>     'count(*)'))
            ->join (
                array ('c' => 'codes'), 'c.code_id = cs.code_id', 
                array ('human_state' => new Zend_Db_Expr("CASE c.state_id WHEN 3 THEN 'active' WHEN 5 THEN 'suspended' ELSE 'inactive' END"), 'c.*')
            )
            ->group('cs.code_id');

---

$sqtemp = $this->_codes->getAdapter()->select()
            ->from (array('cs' => 'code_statuses'), array('total' => 'count(*)'))
            ->join (
                array ('c' => 'codes'), 'c.code_id = cs.code_id', 
                array ('human_state' => new Zend_Db_Expr("CASE     c.state_id WHEN 3 THEN 'active' WHEN 5 THEN 'suspended' ELSE 'inactive' END"), 'c.*')
            )
            ->group('cs.code_id');

---

if (!empty($options['state_id'])):
            if (is_array($options['state_id'])):
                $states = 'cs.state_id=' . implode(' OR cs.state_id=', $options['state_id']);
                $sq->where($states)
                                       ->having(total<=4);
                $sqtemp->where ('cs.state_id=5')
                                            ->having(total<4);
            else:
                $sq->where ('cs.state_id=?', $options['state_id']);
            endif;

当我尝试使用联合时出现问题

$sqfinal=$this->_codes->getAdapter()->select()
                ->union(array($sq,$sqtemp))
                ->order('cs.code_id');

但单独 $sq 和 $sqtemp 工作正常

SQLSTATE[42S22]: Column not found: 1054 Unknown column 'cs.code_id' in 'order clause'

不知道哪里出错了

任何帮助将不胜感激

*编辑

SELECT count(*) AS `total`, 
CASE c.state_id 
WHEN 3 THEN 'active' 
WHEN 5 THEN 'suspended' 
ELSE 'inactive' 
END AS `human_state`, `c`.* 
FROM `code_statuses` AS `cs` 
INNER JOIN `codes` AS `c` 
ON c.code_id = cs.code_id 
WHERE (cs.state_id=1 OR cs.state_id=2 OR cs.state_id=4) 
GROUP BY `cs`.`code_id` HAVING (total<=4) 
UNION 
SELECT count(*) AS `total`, 
CASE c.state_id 
WHEN 3 THEN 'active' 
WHEN 5 THEN 'suspended' 
ELSE 'inactive' 
END AS `human_state`, `c`.* 
FROM `code_statuses` AS `cs` 
INNER JOIN `codes` AS `c` 
ON c.code_id = cs.code_id 
WHERE (cs.state_id=5) 
GROUP BY `cs`.`code_id` 
HAVING (total<4)

union 之前的部分是 $sq，之后的部分是 $sqtemp，两者的组合给出了上面的打印输出 他们两个都与 union in 是一回事

Answer 1

再次查看您的代码后，我怀疑是 oder() 调用联合。您是通过cs.code_id 订购的，select 的任何声明中都没有提及，c.code_id 也没有提及。
尝试将c.code_id 或cs.code_id 添加到构成SELECT't 的UNION，可能考虑使用别名，然后您可以在order 子句中使用该别名。

$sq = $this->_codes->getAdapter()->select()
            ->from(array('cs' => 'code_statuses'),
                   array(
                       'total'     => 'count(*)'
                       'cscodeids' => 'code_ids',
                   ));
//...
$union = $this->_codes->getAdapter()
              ->select()
              ->union(array($sq,$sqtemp))
              ->order('cscodeids');

我相信，这应该可行。我从不同的地方获得了灵感。以下是一些指向我的答案的链接（无法全部找到 ATM）：

• MySQL union and order by help
• Every derived table must have its own alias - error from combination descending MySQL
• Using union and order by clause in mysql
• How to use union in zend db
• Zend_Db union issue：旧的错误报告...包含一些细节