【发布时间】:2018-02-28 06:37:09
【问题描述】:
我在 MYSQL 中创建了如下查询:
select subsql.item_id, subsql.uid, subsql.post_date, subsql.uid_prev,
max(workflow_trans.date) AS pre_date
from (
select item_id, max(date) AS post_date, uid, uid_prev
from workflow_trans
where uid = 'name' and date <= 'date1' and date >= 'date2'
group by item_id, uid, uid_prev
) AS subsql
left join workflow_trans on subsql.item_id = workflow_trans.item_id and
subsql.uid_prev = workflow_trans.uid and subsql.post_date > workflow_trans.date
where workflow_trans.date is not null
group by subsql.item_id, subsql.uid, subsql.post_date, subsql.uid_prev
order by subsql.post_date
In 将其翻译成 Zend DB 格式如下:
$this->db->select()->from(array("subsql" => $this->db->select()
->from(array($this->_name), array('item_id', 'max(date) AS post_date',
'uid', 'uid_prev'))
->where("uid = ?", $username)->where("date >= ?", $tgl1)
->where("date <= ?", $tgl2)
->group(array('item_id', 'uid', 'uid_prev'))),
array('subsql.item_id','subsql.uid',
'subsql.post_date','subsql.uid_prev','max(workflow_trans.date)
as pre_date'))
->joinLeft($this->_name, 'subsql.item_id = workflow_trans.item_id
and subsql.uid_prev = workflow_trans.uid and subsql.post_date >
workflow_trans.date')
->where("workflow_trans.date != ?", null)
->group(array('subsql.item_id', 'subsql.uid', 'subsql.post_date',
'subsql.uid_prev'))
->order(array('subsql.post_date'))
然而 Zend 模型无法工作。我已经重新检查过它,并进行了 3 处更改,但格式仍然存在问题。新鲜的一双锐利的眼睛值得赞赏。
答案更新
大家好,我已经在运行代码下面找到了:
$this->db->select()->from(array("subsql" => $this->db->select()
->from(array($this->_name), array('item_id', 'max(date) AS post_date',
'uid', 'uid_prev'))
->where("uid = ?", $username)->where("date >= ?", $tgl1)
->where("date <= ?", $tgl2)
->group(array('item_id', 'uid', 'uid_prev'))),
array('subsql.item_id','subsql.uid','subsql.post_date','subsql.uid_prev'))
->joinLeft(array($this->_name), 'subsql.item_id = workflow_trans.item_id and
subsql.uid_prev = workflow_trans.uid and
subsql.post_date > workflow_trans.date',
array('max(workflow_trans.date) as pre_date'))
->where("workflow_trans.date is not null")
->group(array('subsql.item_id', 'subsql.uid', 'subsql.post_date',
'subsql.uid_prev'))
->order(array('subsql.post_date'));
您应该在自己的连接函数中定义连接表中的列,当然我在如何处理空值方面弄错了。
【问题讨论】:
-
你的zend和php版本是多少?
标签: mysql zend-framework subquery zend-db