PHP XML - 子节点检索数据答案

【问题标题】：PHP XML - Child nodes retriving dataPHP XML - 子节点检索数据
【发布时间】：2015-06-14 14:15:40
【问题描述】：

我在 php.ini 中遇到了问题。我只能检索第一个标签的值。

这是 XML 文件

<?xml version="1.0" encoding="UTF-8"?>
<Response>
<reservation id="000020" internalId="7366776" > 
   <ccData ccExpireDate="null/null" />
   <reservationDetail id="2_0" currency="" />
   <dayPrice detailId="" roomId="2" day="2015-08-01" />
   <dayPrice detailId="" roomId="2" day="2015-08-02" />
</reservation>
<reservation id="000010" internalId="7366642" >
   <ccData ccCode="Michan" ccNumber="3000000000000" ccExpireDate="12/2016"  />
   <reservationDetail id="2_0" currency="USD" checkin="2015-07-01" />
   <supplement detailId="" roomId="2" description="breakfast" />
   <supplement detailId="" roomId="2" description="wifi" />
   <supplement detailId="" roomId="2" description="transfer" />
   <dayPrice detailId="" roomId="2" day="2015-06-01" />
   <dayPrice detailId="" roomId="2" day="2015-06-02" />
   <guest detailId="" roomId="2" firstName="Rolando" />
   <guest detailId="" roomId="2" firstName="Jessica " />
</reservation>
<reservation id="0005" internalId="7243828" >
   <ccData ccCode="453" ccNumber="34983483649365936539" ccExpireDate="05/2016" />
   <reservationDetail id="2_0" currency="USD" checkin="2015-05-28" />
   <dayPrice detailId="" roomId="2" day="2015-05-29" />
   <dayPrice detailId="" roomId="2" day="2015-05-29" />
</reservation>
</Response>

这是获取数据的 php 代码

//SUPPLEMENT
$Cont=0;
echo "SUP >>>>> ".count($xml->reservation[$x]->supplement)."<br>";  
do {    
    foreach($xml->reservation[$x]->supplement->attributes() as $a => $b) {
        $Texto='[SUPPLEMENT '.sprintf('%02d', $Cont).'] '.$a.'="'.utf8_decode($b).'"';
        echo $Texto."<br>";         
    }
    $Cont++;
} while ($Cont > 99);

这个这个代码输出就是这个

[SUPPLEMENT 00] detailId=""
[SUPPLEMENT 00] roomId="2"
[SUPPLEMENT 00] description="breakfast"

而不是这个

[SUPPLEMENT 00] detailId=""
[SUPPLEMENT 00] roomId="2"
[SUPPLEMENT 01] description="breakfast"
[SUPPLEMENT 01] detailId=""
[SUPPLEMENT 01] roomId="2"
[SUPPLEMENT 01] description="wifi"
[SUPPLEMENT 02] detailId=""
[SUPPLEMENT 02] roomId="2"
[SUPPLEMENT 02] description="transfer"

标签dayPrice和guest也是同样的问题。

谁能帮帮我？

提前谢谢你！！

【问题讨论】：

标签： php xml nodes children

【解决方案1】：

您的foreach 循环仅通过单个supplement 的属性。您需要另一个循环遍历每个 supplement 和下一个循环遍历每个属性：

do {
    foreach($xml->reservation[$x]->supplement as $supplement) {  
      foreach($supplement->attributes() as $a => $b) {
        $Texto='[SUPPLEMENT '.sprintf('%02d', $Cont).'] '.$a.'="'.utf8_decode($b).'"';
        echo $Texto."<br>";         
      }
    }
    $Cont++;
} while ($Cont > 99);

注意：在您的情况下，$x 是 1。

【讨论】：