GraphViz - 如何使子图包含形状？

Question

我有一个图表，它代表一个由两个较小进程组成的大进程。每个较小的过程都由一个子图表示。但是，当我将其中一个子进程（假设“一个”）的结尾连接到另一个（“两个”）的开头时，另一个进程（“两个”）的起始形状最终与“一”的结尾。如何让箭头从一个的末尾指向两个的开头，但将两个的起始形状保持在其簇内？

digraph BigProcess {
   graph [ label="Some big process" ]

   subgraph clusterSubProcess1 {
      graph [ label="Subprocess one", color="red" ]

      start1_1 -> start1_2;
      start1_2 -> start1_3a;
      start1_2 -> start1_3b;
      start1_3a -> start1_4;
      start1_3b -> start1_5;
      start1_4 -> start1_1;
      start1_5 -> start2_1;

   }

   subgraph clusterSubProcess2 {
      graph [ label="Subprocess two", color="blue" ]

      start2_1 -> start2_2;
      start2_2 -> start2_3a;
      start2_2 -> start2_3b;
      start2_3a -> start2_4;
      start2_3b -> start2_5;
      start2_4 -> start2_1;
      start2_5 -> end1;

   }
}

这导致以下结果，我真的希望 start2_1 成为蓝色有界框内的顶部节点。

Answer 1

这是因为第一个子图中的行 start1_5 -> start2_1; 定义了该子图中的 start2_1。您需要在第一个子图中定义 start1_5，但在第二个子图中定义 start2_1 之前将其保持未连接状态。

digraph BigProcess {
   graph [ label="Some big process" ]

   subgraph clusterSubProcess1 {
      graph [ label="Subprocess one", color="red" ]

      start1_1 -> start1_2;
      start1_2 -> start1_3a;
      start1_2 -> start1_3b;
      start1_3a -> start1_4;
      start1_3b -> start1_5;
      start1_4 -> start1_1;
      start1_5;

   }

   subgraph clusterSubProcess2 {
      graph [ label="Subprocess two", color="blue" ]

      start2_1 -> start2_2;
      start2_2 -> start2_3a;
      start2_2 -> start2_3b;
      start2_3a -> start2_4;
      start2_3b -> start2_5;
      start2_4 -> start2_1;
      start2_5 -> end1;

   }

   //Now connect the nodes in the two different subgraphs
   start1_5 -> start2_1;
}