简化 Puppet 清单

Question

我想使用现有的 puppet 模块在服务器上配置多组东西，最简单的例子是：

file { "/var/www/MYVARIABLEHERE":
    ensure => "directory",
}
mysql::db { MYVARIABLEHERE:
    user     => MYVARIABLEHERE,
    password => MYVARIABLEHERE,
    host     => 'localhost',
    grant    => ['all'],
}

有没有办法把它抽象出来，这样我就可以说出一组预定义的选项，然后将它们传递到现有的 puppet 模块中，这样我就不会得到一个数千行长的清单文件？

根据下面的答案我已经设置：

define mySites {
  mysql::db { $name:
    user     => $name,
    password => $name,
    host     => 'localhost',
    grant    => ['all'],
  }

  file { "/var/www/${name}.drupal.dev":
    ensure => "directory",
  }
}

然后我打电话：

mySites {"site": $name => "test", }

并得到以下错误：

Could not parse for environment production: Syntax error at 'name'; expected '}'

Answer 1

您可以使用define 类型来尽可能简化：

define mydef( $usern, $passn) {
  file { "/var/www/$usern":
     ensure => "directory",
  }
  mysql::db { $usern :
      user => $usern,
      password => $passn,
      host => "localhost",
      grant => ['all'],
  }
}

# You have to call the define type for each cases.
mydef{"u1": usern => "john", password => "pass", }

# It might be possible to provide multiple arrays to a define
# type if you use puppet's future parser