使用python转换带大括号的字符串答案

【问题标题】：Convert a string with curly brackets using python使用python转换带大括号的字符串
【发布时间】：2020-06-16 23:51:02
【问题描述】：

我有以下字符串：

{At condition {0}, the value of {1} must be between {2} and {3}.}{{code{min <= 100}}}{{code{min}}}{0}{100}

如何在python中将任何类似的字符串转换为以下格式？

At condition `min <= 100`, the value of `min` must be between 0 and 100.

大括号中的数字应替换为相应的值。如果将值包装到{code{value}} 中，则应添加专用符号 ``。

【问题讨论】：

标签： python regex parsing format

【解决方案1】：

好吧，这有点脆弱/混乱，但考虑到您提供的结构，它应该可以工作。

def convert(s):
    # Find index  of first }{ as this is end of initial string
    idx = s.find('}{')
    initial = s[1:idx]
    # Everything after this index is an argument
    args = s[idx+2:-1]
    args = args.split('}{')
    # Iterate through args and subsitute into initial string
    for i, arg in enumerate(args):
        # Check to see if arg wrapped in {code{}}
        val_idx = arg.find('code{')
        if val_idx != -1:
            # Replace wrapped value with backticks
            arg = '`{}`'.format(arg[val_idx+5:-2])
        # Place arg into proper place in initial string
        initial = initial.replace('{{{}}}'.format(i), arg)

    return initial

调用：

convert('{At condition {0}, the value of {1} must be between {2} and {3}.}{{code{min <= 100}}}{{code{min}}}{0}{100}')
convert('{{0} bar}{foo}')

At condition `min <= 100`, the value of `min` must be between 0 and 100.
foo bar

【讨论】：

不错！谢谢！