Spring mvc Form Submit - 使用新的附加属性加载相同的 jsp（Spring MVC 注释）

Question

我的 jsp 页面中有几个选择下拉菜单。一旦用户从下拉列表中选择了值并单击 Go，应该使用下面的另一个表重新加载相同的 jsp（以及基于从下拉列表中选择的选项的详细信息）。我的jsp如下：

<form:form method="post" modelAttribute="clientForm" commandName = "clientForm" action="/editFeeMaintenance">

    <table>
        <tbody>
            <tr>
                <td><strong><bean:message key="Select Client" /> </strong></td>
                <td width="8%" height="6">&#160;</td>
                <td align="left"><form:select path="client">
                        <form:option value="0">------Select Client ------ </form:option>
                        <form:options items="${clientsList}">
                        </form:options>
                    </form:select></td>
                    <td><form:errors path="client" cssStyle="color: #ff0000;" /></td>
            </tr><br>

            <tr>
                <td>
                &#160;<input type="submit" value="Search" onclick="getClient()">
                </td>   
            </tr>
        </tbody>
    </table>
</form:form>

 <script language = "JavaScript">
    function getClient()
{

    var clientObj = document.getElementById("client");

    console.log("client value : "+clientObj);
    clientObj.actionType.value = submitType;

    return false;
    //formObj.submit();
}
</script>

这是我的控制器：

@Controller
public class MyController {

@Autowired
private MyService myService;

 @RequestMapping(value="/addFeeMaintainance.do",method =     RequestMethod.GET)
 protected ModelAndView populateValues(HttpServletRequest request, HttpServletResponse response) throws Exception {

MyForm = new MyForm();

MyForm.setClientList(MyService.getClientList();

ModelAndView model = new ModelAndView("feeMaintenance");
model.addObject("clientForm",MyForm);
model.addObject("clientsList",Myform.getClientList());

return model;
 }

  @RequestMapping(value="/editFeeMaintainance",method = RequestMethod.POST)
   protected ModelAndView selectValues(@RequestParam String client,
    @ModelAttribute("clientForm") MyForm paswForm ) throws Exception {

System.out.println("Account selected : "+paswForm.getClient());

ModelAndView model = new ModelAndView("feeMaintenance");
model.addObject("clientForm",MyForm);
return model;
 }
 }

我无法刷新表单并转到 POST 方法。让我知道缺少什么。 还有web.xml：

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>classpath:spring/applicationContext*.xml</param-value>
</context-param>
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>


<servlet>
    <servlet-name>Dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>

    <load-on-startup>1</load-on-startup>
</servlet>

dispatcher servlet 文件如下：

<mvc:annotation-driven />

<context:annotation-config />
<context:component-scan     base-package="com.controller,com.serviceImpl,com.daoImpl" />


<bean class="org.springframework.web.servlet.view.UrlBasedViewResolver"
    id="viewResolver">
    <property name="viewClass">
        <value>
            org.springframework.web.servlet.view.tiles2.TilesView
        </value>
    </property>
</bean>
<bean class="org.springframework.web.servlet.view.tiles2.TilesConfigurer"
    id="tilesConfigurer">
    <property name="definitions">
        <list>
            <value>/WEB-INF/plugin/impl/tiles/springtiles-defs.xml</value>
        </list>
    </property>
</bean>

<bean id="dataSource" class="org.springframework.jndi.JndiObjectFactoryBean">
    <property name="jndiName" value="jdbc/myDS" />
</bean>
<bean
    class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean"
    id="sessionFactory">
    <property name="dataSource" ref="dataSource"></property>

     <property name="configLocation">
        <value>/WEB-INF/config/hibernate.cfg.xml</value>
    </property>

    <property name="configurationClass">
        <value>org.hibernate.cfg.AnnotationConfiguration</value>
    </property>

    <property name="hibernateProperties">
        <props>
            <!-- <prop key="current_session_context_class">thread</prop> -->
            <prop key="hibernate.dialect">org.hibernate.dialect.OracleDialect </prop>
            <prop key="hibernate.show_sql">true</prop>
            <prop key="hibernate.hbm2ddl.auto">update</prop>
        </props>
    </property>
</bean>

<bean id="transactionManager"
    class="org.springframework.orm.hibernate3.HibernateTransactionManager">
    <property name="sessionFactory" ref="sessionFactory"></property>
</bean>

<tx:annotation-driven transaction-manager="transactionManager"/>   

Answer 1

你的代码看起来不错，从客户端和服务器端（我没有检查你是否正确映射了你的表单对象，如果你的控制器有 RequestMapping 值你还没有发布），但唯一的问题是表单的操作，在你没有在action中应用指定的URL，所以每当你点击按钮时，它只是调用JS函数而不提交表单。所以如果你能改变

<form:form method="post" modelAttribute="clientForm" commandName = "clientForm" action="">

到

<form:form method="post" modelAttribute="clientForm" commandName = "clientForm" action="YOUR_URL">

并查看相关答案here

或查看本教程here，每当表单在同一页面中提交时，他都会在其中重定向

编辑：

在您的 web.xml 中配置一个名为 Dispatcher 的 servlet，然后在下面将请求映射应用到：

 <servlet-mapping>
    <servlet-name>paswDispatcher</servlet-name>
    <url-pattern>*.do</url-pattern>
</servlet-mapping>

如果您有 2 个 servlet，那么您缺少一些配置，否则如果这是唯一的 servlet，请将其更改为

<servlet-mapping>
    <servlet-name>Dispatcher</servlet-name>
    <url-pattern>/*</url-pattern>
</servlet-mapping>