我在此 Python 代码中找不到的错误在哪里？ [关闭]

Question

我找不到错误。我将非常感谢一些帮助！提前谢谢你。

""" 该程序要求用户提供三种成分， 三份量和份数，以及 确定每种成分需要多少 送达指定份数。 """

ingredient_one = input("What is the first ingredient?: ")
ing_one_oz = int(input("How many ounces of this ingredient?: ")

ingredient_two = input("What is the second ingredient?: ")
ing_two_oz = int(input("How many ounces of this ingredient?: ")

ingredient_three = input("What is the third ingredient?: ")
ing_three_oz = int(input("How many ounces of this ingredient?: ")



servings_amt = int(input("How many servings would you like?: ")

ing_one_oz = ing_one_oz * servings_amt
ing_two_oz = ing_two_oz * servings_amt
ing_three_oz = ing_three_oz * servings_amt

print("In order to make " + str(servings_amt) + " servings of your recipe, you will need " + str(ing_one_oz) + " ounces of " /
+ str(ingredient_one) + ", " + str(ing_two_oz) + " ounces of " + str(ingredient_two) + ", and " + str(ing_three_oz) /
+ " ounces of " + str(ingredient_three) + ".")

输出在第 3 行显示语法错误，该错误以变量成分_two 开头。 第 1 行已经通过“正确”，但第 3 行没有，尽管它们实际上是相同的。

Answer 1

我不是python专家，但是

int(input("How many ounces of this ingredient?: ")

不需要第二个“)”？

Answer 2

您的错误在第 2 行。您需要在 ing_one_oz 末尾多加一个括号

ing_one_oz = int(input("How many ounces of this ingredient?: ")

Python 对拾取前几行出现的错误很有趣。

Answer 3

错误位于第 #2、#4、#6、#7 行，即 ing_one_oz、ing_two_oz、ing_three_oz、servings_amt。在您将输入类型转换为“int”的地方关闭括号