【发布时间】:2016-06-17 12:37:19
【问题描述】:
我遇到的几乎所有类似问题都建议使用PIVOT,但我不明白如何在我的情况下使用它。
这是我的查询
SELECT
SUM(CONVERT(INT,H01)) as H01,
SUM(CONVERT(INT,H02)) as H02,
SUM(CONVERT(INT,H03)) as H03,
SUM(CONVERT(INT,H04)) as H04,
SUM(CONVERT(INT,H05)) as H05,
SUM(CONVERT(INT,H06)) as H06,
SUM(CONVERT(INT,H07)) as H07,
SUM(CONVERT(INT,H08)) as H08,
SUM(CONVERT(INT,H09)) as H09,
SUM(CONVERT(INT,H10)) as H10,
SUM(CONVERT(INT,H11)) as H11,
SUM(CONVERT(INT,H12)) as H12,
SUM(CONVERT(INT,H13)) as H13,
SUM(CONVERT(INT,H14)) as H14,
SUM(CONVERT(INT,H15)) as H15
FROM
IslemFisi
WHERE
(H01 = 1) OR (H02 = 1) OR (H03 = 1) OR (H04 = 1) OR
(H05 = 1) OR (H06 = 1) OR (H07 = 1) OR (H08 = 1) OR
(H09 = 1) OR (H10 = 1) OR (H11 = 1) OR (H12 = 1) OR
(H13 = 1) OR (H14 = 1) OR (H15 = 1)
返回这个结果集
+-------+------+------+------+-----+------+-----+------+-----+-----+------+-----+-----+------+-------+
| H01 | H02 | H03 | H04 | H05 | H06 | H07 | H08 | H09 | H10 | H11 | H12 | H13 | H14 | H15 |
+-------+------+------+------+-----+------+-----+------+-----+-----+------+-----+-----+------+-------+
| 11802 | 2239 | 1575 | 2230 | 833 | 3189 | 152 | 4234 | 617 | 428 | 2211 | 263 | 783 | 3954 | 15922 |
+-------+------+------+------+-----+------+-----+------+-----+-----+------+-----+-----+------+-------+
我想把它放在一个列中,但不知道怎么做。使用 pivot 似乎需要一些聚合函数,但此时我没有任何要聚合的东西。
【问题讨论】:
标签: sql-server transpose