Roblox 制作功能运行不止一次答案

【问题标题】：Roblox making functions run more than onceRoblox 制作功能运行不止一次
【发布时间】：2018-09-14 19:25:03
【问题描述】：

我的代码：

local UIS = game:GetService("UserInputService")
local Player = game.Players.LocalPlayer
local Mouse = Player:GetMouse()
local Activation = 
Instance.new("Sound",game.Players.LocalPlayer.Character.Head)
local char = Player.Character
local hum = char.Humanoid
local root = char.HumanoidRootPart

UIS.InputBegan:Connect(function(input)
if input.KeyCode == Enum.KeyCode.F then
    local animation = Instance.new("Animation")
    animation.AnimationId = "rbxassetid://1581972610"
    local animTrack = hum:LoadAnimation(animation)
    animTrack:Play()
    Activation.SoundId = "rbxassetid://1581091676" --Plays Mangekyou Sharingan Activation Sound.
    Activation:Play()
    wait(0.3)       
    game.Players.LocalPlayer.Character.Head.face.Texture = "rbxassetid://76285632" --When F is pressed, face texture changes to sharingan decal.
    game:GetService("Chat"):Chat(Player.Character.Head, "Mangekyou Sharingan!")
end
end)

UIS.InputBegan:Connect(function(input)
if input.KeyCode == Enum.KeyCode.R then
    Activation.SoundId = "rbxassetid://1580990602" --Plays Amaterasu Activation Sound.
    Activation:Play()
    game:GetService("Chat"):Chat(Player.Character.Head, "Amaterasu!")
    local Target = Instance.new("Part") --makes a part
    Target.CFrame = Mouse.Hit; --Makes part spawn at the mouse's current location in game
    Target.Parent = game.Workspace
    Target.Transparency = 1 
    Target.Anchored = true 
    Target.CanCollide = false 



    local Amaterasu = Instance.new("Fire")
    Amaterasu.Parent = game.Workspace.Part
    Amaterasu.Color = Color3.new(0,0,0)
    Amaterasu.SecondaryColor = Color3.new(0,0,0) --amaterasu properties
    Amaterasu.Size = 25

    local R = Instance.new("RocketPropulsion") --rocket propulsion, parents amaterasu
    R.Parent = Amaterasu
    R.MaxThrust = 300
    R.ThrustP = 30
    R:Fire()
end
end)

UIS.InputBegan:Connect(function(input)
if input.KeyCode == Enum.KeyCode.G then
    game.Players.LocalPlayer.Character.Head.face.Texture = "rbxassetid://22557247" --When G is pressed, face texture changes back to normal.(leaves face blank isnt working :/)
end
end)

我正在处理这个脚本中的第二个函数，如果按下“r”键就会激活该函数。该功能通过按“r”键使部分产生到鼠标当前位置，其中包含火焰。

这一切正常，除了第一次按“r”在鼠标位置生成零件后，如果我将鼠标的位置移动到另一个区域并再次按“r”，它会重复函数中的所有内容，但不会t 更改到新位置。

【问题讨论】：

你的意思是这行`Target.CFrame = Mouse.Hit`导致相同的位置吗？好吧，您必须检查此处分配的内容。可能是Mouse实例每次都需要更新。

标签： lua scripting roblox

【解决方案1】：

您应该尝试在按下 R 键时运行的函数中运行 Mouse = Player:GetMouse() 以更新鼠标的位置。您更新后的活动如下所示：

UIS.InputBegan:Connect(function(input)
if input.KeyCode == Enum.KeyCode.R then
    Mouse = Player:GetMouse() --This line updates the mouse and presumably, its location.
    Activation.SoundId = "rbxassetid://1580990602"Sound.
    Activation:Play()
    game:GetService("Chat"):Chat(Player.Character.Head, "Amaterasu!")
    local Target = Instance.new("Part")
    Target.CFrame = Mouse.Hit;
    --All the other stuff you're doing goes here

这样，鼠标的位置会在每次输入 if 块时更新（即每次用户按 R 键时）。

【讨论】：