它并不完美，但我为我在 C# 中的测试编写了这个助手：
using System;
using System.Collections.Generic;
using System.Threading;
using System.Threading.Tasks;
namespace Proto.Promises.Tests.Threading
{
public class ThreadHelper
{
public static readonly int multiThreadCount = Environment.ProcessorCount * 100;
private static readonly int[] offsets = new int[] { 0, 10, 100, 1000 };
private readonly Stack<Task> _executingTasks = new Stack<Task>(multiThreadCount);
private readonly Barrier _barrier = new Barrier(1);
private int _currentParticipants = 0;
private readonly TimeSpan _timeout;
public ThreadHelper() : this(TimeSpan.FromSeconds(10)) { } // 10 second timeout should be enough for most cases.
public ThreadHelper(TimeSpan timeout)
{
_timeout = timeout;
}
/// <summary>
/// Execute the action multiple times in parallel threads.
/// </summary>
public void ExecuteMultiActionParallel(Action action)
{
for (int i = 0; i < multiThreadCount; ++i)
{
AddParallelAction(action);
}
ExecutePendingParallelActions();
}
/// <summary>
/// Execute the action once in a separate thread.
/// </summary>
public void ExecuteSingleAction(Action action)
{
AddParallelAction(action);
ExecutePendingParallelActions();
}
/// <summary>
/// Add an action to be run in parallel.
/// </summary>
public void AddParallelAction(Action action)
{
var taskSource = new TaskCompletionSource<bool>();
lock (_executingTasks)
{
++_currentParticipants;
_barrier.AddParticipant();
_executingTasks.Push(taskSource.Task);
}
new Thread(() =>
{
try
{
_barrier.SignalAndWait(); // Try to make actions run in lock-step to increase likelihood of breaking race conditions.
action.Invoke();
taskSource.SetResult(true);
}
catch (Exception e)
{
taskSource.SetException(e);
}
}).Start();
}
/// <summary>
/// Runs the pending actions in parallel, attempting to run them in lock-step.
/// </summary>
public void ExecutePendingParallelActions()
{
Task[] tasks;
lock (_executingTasks)
{
_barrier.SignalAndWait();
_barrier.RemoveParticipants(_currentParticipants);
_currentParticipants = 0;
tasks = _executingTasks.ToArray();
_executingTasks.Clear();
}
try
{
if (!Task.WaitAll(tasks, _timeout))
{
throw new TimeoutException($"Action(s) timed out after {_timeout}, there may be a deadlock.");
}
}
catch (AggregateException e)
{
// Only throw one exception instead of aggregate to try to avoid overloading the test error output.
throw e.Flatten().InnerException;
}
}
/// <summary>
/// Run each action in parallel multiple times with differing offsets for each run.
/// <para/>The number of runs is 4^actions.Length, so be careful if you don't want the test to run too long.
/// </summary>
/// <param name="expandToProcessorCount">If true, copies each action on additional threads up to the processor count. This can help test more without increasing the time it takes to complete.
/// <para/>Example: 2 actions with 6 processors, runs each action 3 times in parallel.</param>
/// <param name="setup">The action to run before each parallel run.</param>
/// <param name="teardown">The action to run after each parallel run.</param>
/// <param name="actions">The actions to run in parallel.</param>
public void ExecuteParallelActionsWithOffsets(bool expandToProcessorCount, Action setup, Action teardown, params Action[] actions)
{
setup += () => { };
teardown += () => { };
int actionCount = actions.Length;
int expandCount = expandToProcessorCount ? Math.Max(Environment.ProcessorCount / actionCount, 1) : 1;
foreach (var combo in GenerateCombinations(offsets, actionCount))
{
setup.Invoke();
for (int k = 0; k < expandCount; ++k)
{
for (int i = 0; i < actionCount; ++i)
{
int offset = combo[i];
Action action = actions[i];
AddParallelAction(() =>
{
for (int j = offset; j > 0; --j) { } // Just spin in a loop for the offset.
action.Invoke();
});
}
}
ExecutePendingParallelActions();
teardown.Invoke();
}
}
// Input: [1, 2, 3], 3
// Ouput: [
// [1, 1, 1],
// [2, 1, 1],
// [3, 1, 1],
// [1, 2, 1],
// [2, 2, 1],
// [3, 2, 1],
// [1, 3, 1],
// [2, 3, 1],
// [3, 3, 1],
// [1, 1, 2],
// [2, 1, 2],
// [3, 1, 2],
// [1, 2, 2],
// [2, 2, 2],
// [3, 2, 2],
// [1, 3, 2],
// [2, 3, 2],
// [3, 3, 2],
// [1, 1, 3],
// [2, 1, 3],
// [3, 1, 3],
// [1, 2, 3],
// [2, 2, 3],
// [3, 2, 3],
// [1, 3, 3],
// [2, 3, 3],
// [3, 3, 3]
// ]
private static IEnumerable<int[]> GenerateCombinations(int[] options, int count)
{
int[] indexTracker = new int[count];
int[] combo = new int[count];
for (int i = 0; i < count; ++i)
{
combo[i] = options[0];
}
// Same algorithm as picking a combination lock.
int rollovers = 0;
while (rollovers < count)
{
yield return combo; // No need to duplicate the array since we're just reading it.
for (int i = 0; i < count; ++i)
{
int index = ++indexTracker[i];
if (index == options.Length)
{
indexTracker[i] = 0;
combo[i] = options[0];
if (i == rollovers)
{
++rollovers;
}
}
else
{
combo[i] = options[index];
break;
}
}
}
}
}
}
示例用法：
[Test]
public void DeferredMayBeBeResolvedAndPromiseAwaitedConcurrently_void0()
{
Promise.Deferred deferred = default(Promise.Deferred);
Promise promise = default(Promise);
int invokedCount = 0;
var threadHelper = new ThreadHelper();
threadHelper.ExecuteParallelActionsWithOffsets(false,
// Setup
() =>
{
invokedCount = 0;
deferred = Promise.NewDeferred();
promise = deferred.Promise;
},
// Teardown
() => Assert.AreEqual(1, invokedCount),
// Parallel Actions
() => deferred.Resolve(),
() => promise.Then(() => { Interlocked.Increment(ref invokedCount); }).Forget()
);
}