用户询问您要接受多少输入，然后以 mips 显示他们的总和答案

【问题标题】：User ask how many input you want to take and then show their sum in mips用户询问您要接受多少输入，然后以 mips 显示他们的总和
【发布时间】：2017-10-26 08:24:12
【问题描述】：

我想用 mips 编写一个程序，用户将在其中输入他想要输入的数量。最后，程序将打印输入的总和。

这是我的代码：

 .data

    myMessage:  .asciiz "ENTER numbers you want to sum\n"
    value:      .asciiz "ENTER  Value \n"

    sum :       .word 0


 .text

    li $v0, 4
    la $a0, myMessage
    syscall

    li $v0, 5
    syscall

    move $t0, $v0         #num of time user will enter num

    la $t1, 0         #count value first initiallize to 0

see:
    bne $t1,$t0,add         #checking if  count is less than the num of value 



    li  $v0, 1              #printing sum finally
    la $a0, ($s2)

add:
    li $v0,4
    la $a0,value
    syscall

    li $v0,5
    syscall

    move $t3,$v0


    la $a1, sum     #load address of 'bal' in '$a1'
    lw $s3, 0($a1)      #load sum from '$a1' to '$s2' (initially 0)
    add $s3, $s3, $t3   #adding the sum 
    sw $s2, 0($a1)      #load latest sum ('$s2') in .word balance ('$a1')

    addi $t1,$t1,1                    inc in count

    j see

问题是程序在输入所需数量后并没有停止，而是继续请求新的输入。

【问题讨论】：

标签： loops mips

【解决方案1】：

.data      # Data declaration section

    instring1:    .asciiz  "ENTER numbers you want to sum\n"
    instring2:    .asciiz  "Enter value\n"
    outstring:    .asciiz  "Sum: "

.text#
main: 
#Print instring1
    li $v0, 4           # system call code for printing string = 4
    la $a0, instring1   # load address of string to be printed into $a0
    syscall             # call operating system to perform operation in $v0
                        #     syscall takes its arguments from $a0, $a1,

#Taking n as input
    li $v0, 5 # read int
    syscall
    move $s0, $v0 # the result of the syscall is stored in v0
                # we move it to t0 to prevent overwriting

#Creation heap memory
    mul $t1, $s0, 4
    li $v0, 9
    move $a0, $t1
    syscall
    move $s1, $v0
        

#Print instring2
    li $v0, 4           # system call code for printing string = 4
    la $a0, instring2  # load address of string to be printed into $a0
    syscall             # call operating system to perform operation in $v0
                        #     syscall takes its arguments from $a0, $a1,

    li   $s2, 0         # $s2 is the index, and loop induction variable
        
Start_Input:  
    bge  $s2, $s0, End_Input

    li $v0, 5           # Read integer values
    syscall
    
    mul  $t0, $s2, 4    # $t0 is the offset
    add  $t1, $s1, $t0  # $t1 is the address of desired index
    sw   $v0, ($t1)     # store the value in the array
    addi $s2, $s2, 1    # increment the index        
    j    Start_Input

End_Input:
    add $t0, $zero, $zero # i is initialized to 0, $t0 = 0
    add $s2, $zero, $zero # sum = 0
    beq $s0, $zero, print_sum # if number = 0 then goto print_sum

Loop: #stuff
    mul $t1, $t0, 4
    add  $t2, $s1, $t1
    lw $t3, ($t2)
    add $s2, $s2, $t3

    addi $t0, $t0, 1 # i ++
    slt $t1, $t0, $s0 # $t1 = 1 if i < n
    bne $t1, $zero, Loop # go to Loop if i < n

#Print Sum
print_sum:
    li $v0, 4           # system call code for printing string = 4
    la $a0, outstring   # load address of string to be printed into $a0
    syscall             # call operating system to perform operation in $v0
                        #     syscall takes its arguments from $a0, $a1,
    li $v0 1 # print int
    move $a0 $s2
    syscall

#Exit Syscall
EXIT:
    li $v0 10# exit
    syscall

这是工作代码。提供注释以理解代码。

【讨论】：

【解决方案2】：

.data 
myMessage:.asciiz "ENTER numbers you want to sum\n" 
value:.asciiz "ENTER  Value: "
show: .asciiz "\nSum is: "
.text 
li $v0,4 
la $a0,myMessage 
syscall 
li $v0,5 
syscall
move $t0,$v0    #num of time user will enter num
la $t1, 0   #count value first initiallize to 0
la $t5, 0
see:
bne $t1,$t0,add #checking if  count is less than the num of value
li $v0, 4
la $a0, show
syscall     #print message "Sum is: "
li $v0, 1
move $a0, $t5
syscall     #print the result
j end
add: 
li $v0,4 
la $a0,value 
syscall
li $v0, 5
syscall
add $t5, $t5, $v0
sub $t0, $t0, 1
j see
end:

【讨论】：