SQL TOP 10 排名查询需要帮助答案

【问题标题】：SQL TOP 10 Ranking Query Help RequiredSQL TOP 10 排名查询需要帮助
【发布时间】：2010-02-12 11:16:47
【问题描述】：

我有下面的代码，我试图找出上个月使用的前 10 台服务器，但是遇到了问题，SQL 不太好。如果可能，需要一些帮助或建议。

我在排名前 10 的应用程序上实现了这一点，但不知道如何在排名前 10 的服务器上实现这一点。

SELECT TOP 10 dbo_LU_SERVERNAME.SERVERNAME, Count(*) AS SessionNumbers
FROM dbo_LU_SERVERNAME INNER JOIN dbo_SDB_SESSION ON dbo_LU_SERVERNAME.PK_SERVERNAMEID = dbo_SDB_SESSION.FK_SERVERNAMEID
WHERE (((dbo_SDB_SESSION.SESSIONSTART) Between Now() And DateAdd("d",-30,Now())))
GROUP BY dbo_LU_SERVERNAME.SERVERNAME
ORDER BY Count(*) DESC;

UNION ALL SELECT "Other" AS SERVERNAME, Count(*) AS SessionNumbers
FROM (dbo_LU_SERVERNAME
INNER JOIN dbo_SDB_SESSION  
ON dbo_LU_SERVER.PK_SERVERID = dbo_SDB_SESSION.FK_SERVERID)  
LEFT JOIN (SELECT TOP 10 dbo_LU_SERVERNAME.SERVERNAME, Count(*) AS SessionNos 
           FROM dbo_LU_SERVERNAME
           INNER JOIN dbo_SDB_SESSION 
           ON dbo_LU_SERVER.PK_SERVERID = dbo_SDB_SESSION.FK_SERVERID
           WHERE (((dbo_SDB_SESSION.SESSIONSTART) Between Now() And DateAdd("d",-31,Now())))
           GROUP BY dbo_LU_SERVERNAME.SERVERNAME
           ORDER BY Count(*) DESC) AS s  ON dbo_LU_SERVERNAME.SERVERNAME = s.SERVERNAME

WHERE s.SERVERNAME Is Null
GROUP BY "Other";

这是适用于前 10 个应用程序的 SQL。

SELECT TOP 10 dbo_LU_APPNAME.APPNAME, Count(*) AS SessionNos
FROM dbo_LU_APPNAME INNER JOIN dbo_SDB_SESSION ON dbo_LU_APPNAME.PK_APPNAMEID = dbo_SDB_SESSION.FK_APPNAMEID
WHERE (((dbo_SDB_SESSION.SESSIONSTART) Between Now() And DateAdd("d",-30,Now())))
GROUP BY dbo_LU_APPNAME.APPNAME
ORDER BY Count(*) DESC;

UNION ALL SELECT "Other" AS APPNAME, Count(*) AS SessionNos 
FROM (dbo_LU_APPNAME
INNER JOIN dbo_SDB_SESSION  
ON dbo_LU_APPNAME.PK_APPNAMEID = dbo_SDB_SESSION.FK_APPNAMEID)  
LEFT JOIN (SELECT TOP 10 dbo_LU_APPNAME.APPNAME, Count(*) AS SessionNos 
           FROM dbo_LU_APPNAME
           INNER JOIN dbo_SDB_SESSION 
           ON dbo_LU_APPNAME.PK_APPNAMEID = dbo_SDB_SESSION.FK_APPNAMEID
           WHERE (((dbo_SDB_SESSION.SESSIONSTART) Between Now() And DateAdd("d",-31,Now())))
           GROUP BY dbo_LU_APPNAME.APPNAME
           ORDER BY Count(*) DESC) AS s  ON dbo_LU_APPNAME.APPNAME = s.APPNAME

WHERE s.APPNAME Is Null
GROUP BY "Other";

请注意，这些表格的相关性如下： dbo_LU_SERVER ---> FK_SERVERNAMEID, PK_SERVERID dbo_LU_SERVERNAME ---> PK_SERVERNAMEID dbo.SDB.SESSION ---> FK_SERVERID

我不确定自己做错了什么。

请帮忙。

谢谢

【问题讨论】：

您在问题中没有解释的是 UNION ALL 的使用。我猜测这是未包含在前 10 名列表中的所有服务器会话的总数。因此，您的最终列表将是 11 行，前 10 台服务器，然后是所有其他会话的计数。
您已使用 SQL、ms-access 和 visual-basic 标记您的问题。我假设您正在为 Access 编写此查询，但是 VB 部分是从哪里来的？
这是来自stackoverflow.com/questions/2205902/… 不是吗？
是的，看起来一样。也许这个问题应该结束了。
我想问题是添加了日期，所以无论日期如何，Other 都包括所有内容。

标签： sql ms-access ranking

【解决方案1】：

我设法回答了我的问题。

SELECT TOP 10 dbo_LU_SERVERNAME.SERVERNAME, Count(*) AS SessionNumbers
FROM dbo_LU_SERVERNAME INNER JOIN dbo_SDB_SESSION ON dbo_LU_SERVERNAME.PK_SERVERNAMEID = dbo_SDB_SESSION.FK_SERVERID
WHERE (((dbo_SDB_SESSION.SESSIONSTART) Between Now() And DateAdd("d",-30,Now())))
GROUP BY dbo_LU_SERVERNAME.SERVERNAME
ORDER BY Count(*) DESC;

UNION ALL SELECT "Other" AS SERVERNAME, Count(*) AS SessionNumbers
FROM  (dbo_LU_SERVERNAME INNER JOIN dbo_SDB_SESSION ON dbo_LU_SERVERNAME.PK_SERVERNAMEID = dbo_SDB_SESSION.FK_SERVERID)
LEFT JOIN (SELECT TOP 10 dbo_LU_SERVERNAME.SERVERNAME, Count(*) AS SessionNos 
           FROM dbo_LU_SERVERNAME INNER JOIN dbo_SDB_SESSION ON dbo_LU_SERVERNAME.PK_SERVERNAMEID = dbo_SDB_SESSION.FK_SERVERID
           WHERE (((dbo_SDB_SESSION.SESSIONSTART) Between Now() And DateAdd("d",-31,Now())))
           GROUP BY dbo_LU_SERVERNAME.SERVERNAME
           ORDER BY Count(*) DESC) AS a  ON dbo_LU_SERVERNAME.SERVERNAME = a.SERVERNAME

WHERE a.SERVERNAME Is Null
GROUP BY "Other";

感谢您的 cmets，我之前确实问过另一个问题，几乎与此相同，但另一个问题是关于两个相关实体，这是三个相关实体。

再次感谢

干杯:)

【讨论】：