【发布时间】:2015-09-09 07:13:05
【问题描述】:
我有一个包含以下数据的表格:
mysql> describe Post;
+-------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| user_id | int(11) | NO | MUL | NULL | |
| post_date | datetime | NO | | NULL | |
| in_reply_to | int(11) | YES | | NULL | |
| text | varchar(160) | NO | | NULL | |
+-------------+--------------+------+-----+---------+----------------+
mysql> select id as "Row ID", user_id as "User ID", post_date as "Post Date", IF(in_reply_to is NULL, "None", in_reply_to) as "In Reply To Post ID:", CONCAT(LEFT(text,40),"...") as "Post Text" from Post;
+--------+---------+---------------------+----------------------+---------------------------------------------+
| Row ID | User ID | Post Date | In Reply To Post ID: | Post Text |
+--------+---------+---------------------+----------------------+---------------------------------------------+
| 1 | 1 | 2015-08-14 20:38:00 | None | This is the original test post that I pu... |
| 2 | 2 | 2015-08-14 20:39:00 | None | This is the second post that I put into ... |
| 3 | 5 | 2015-08-14 22:00:00 | 1 | Hahaha, that post was hilarious. I canno... |
| 4 | 4 | 2015-08-14 23:00:00 | 1 | Today I saw a cat jump off the roof, ont... |
| 5 | 4 | 2015-08-14 23:00:00 | None | Today I saw a cat jump off the roof, ont... |
| 27 | 1 | 2015-09-08 05:53:40 | 2 | This is a mad reply ay... |
| 28 | 1 | 2015-09-08 11:24:05 | None | Yolo Swag... |
+--------+---------+---------------------+----------------------+---------------------------------------------+
7 rows in set (0.05 sec)
如果您不确定它们代表什么,每列都有一个描述。对于这个问题,我关心的两列是id 和in_reply_to。
in_reply_to 是一个NULLABLE FK 整数,它在同一个表中引用id;如果in_reply_to是NULL,则表示该帖子是原始帖子,如果是整数值,则表示回复帖子,表示回复帖子的ID。
在下面的示例中,有 4 个原始帖子(1、2、5、28)和 3 个回复(3、4、27),即 3 是对 1 的回复,4 也是对 1 的回复,以及 27是对 2 的回复。我希望执行一个 SQL 查询,该查询会产生如下输出:
其中Num Replies 是COUNT,表示同一个表中有多少行的in_reply_to 等于id;如果没有对该帖子的回复,则显示 0(即,没有行包含特定帖子的 ID 作为其in_reply_to 列。
谢谢。
解决方案(根据安德斯的回答):
mysql> SELECT Post.id, Post.user_id, Post.post_date, Post.in_reply_to, CONCAT(LEFT(Post.text,40)), IF(counts.count IS NULL, 0, counts.count) AS 'Num of Replies' FROM Post LEFT JOIN (SELECT in_reply_to AS id, COUNT(*) AS count FROM Post WHERE in_reply_to IS NOT NULL GROUP BY in_reply_to) AS counts ON Post.id = counts.id;
+----+---------+---------------------+-------------+------------------------------------------+----------------+
| id | user_id | post_date | in_reply_to | CONCAT(LEFT(Post.text,40)) | Num of Replies |
+----+---------+---------------------+-------------+------------------------------------------+----------------+
| 1 | 1 | 2015-08-14 20:38:00 | NULL | This is the original test post that I pu | 2 |
| 2 | 2 | 2015-08-14 20:39:00 | NULL | This is the second post that I put into | 1 |
| 3 | 5 | 2015-08-14 22:00:00 | 1 | Hahaha, that post was hilarious. I canno | 0 |
| 4 | 4 | 2015-08-14 23:00:00 | 1 | Today I saw a cat jump off the roof, ont | 0 |
| 5 | 4 | 2015-08-14 23:00:00 | NULL | Today I saw a cat jump off the roof, ont | 0 |
| 27 | 1 | 2015-09-08 05:53:40 | 2 | This is a mad reply ay | 0 |
| 28 | 1 | 2015-09-08 11:24:05 | NULL | Random Text | 0 |
+----+---------+---------------------+-------------+------------------------------------------+----------------+
7 rows in set (0.00 sec)
【问题讨论】:
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您的第一张图片已损坏。请以文本而不是图像的形式包含所有数据。
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@Anders 我现在已经替换了它。