【发布时间】:2016-08-13 14:19:13
【问题描述】:
我是 Swift 的新手,但我正在学习一些示例,例如如何制作登录应用程序,将用户名和密码字段发送到 php 文件并返回 json 响应。
当我打印我的 responseString 时,我得到:
[{"userid":1,"username":"rodrigo","password":"minhoca","groupname":"couple"}]
但是当我尝试解析 json 时,我永远无法设置用户名变量,因为永远不会进入代码的那部分,我只是得到“这里”
感谢您的帮助
func sendLoginInfo(username: String, password: String) -> String{
if let url = URL(string: "myphpurl"){
let request = NSMutableURLRequest(url:url)
request.httpMethod = "POST";// Compose a query string
let postString = "?username=\(myUsername)&password=\(myPassword)"
request.httpBody = postString.data(using: String.Encoding.utf8)
let task = URLSession.shared.dataTask(with:request as URLRequest){
data, response, error in
if error != nil{
print("1\(error)")
}
else{
let responseString = NSString(data: data!, encoding: String.Encoding.utf8.rawValue)
print("response string = \(responseString!)")
}
do {
if let convertedJsonIntoDict = try JSONSerialization.jsonObject(with: data!, options: []) as? NSDictionary {
// Print out dictionary
print(convertedJsonIntoDict)
// Get value by key
let firstNameValue = convertedJsonIntoDict["username"] as? String
print("here = \(firstNameValue!)")
}
else{
print("here")
}
} catch let error as NSError {
print(error.localizedDescription)
}
}
task.resume()
}
return ""
}
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