打开我的联系人时如何直接拨打电话

Question

当我点击按钮选择联系人选择联系人不拨打号码时的问题，我想在选择号码时直接拨打电话

buttoncontact = findViewById(R.id.choosecontact);


public void choosecontact1 (View view){

     Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);

   intent.setType(ContactsContract.CommonDataKinds.Phone.CONTENT_TYPE);
    startActivityForResult(intent, PICK_CONTACT)


}

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    String call = buttoncontact.getText().toString();


    if ((requestCode == 1) && (resultCode == RESULT_OK)) {
        Cursor cursor = null;
        try {
            Uri uri = data.getData();
            cursor = getContentResolver().query(uri, new String[] { ContactsContract.CommonDataKinds.Phone.NUMBER }, null, null, null);
            if (cursor != null && cursor.moveToNext()) {
                String phone = cursor.getString(0);

// 该代码的问题

                Intent intent = new Intent(Intent.ACTION_CALL);
                intent.setData(Uri.parse(String.valueOf("tel:" + CONTENT_TYPE)));

//我要打开手机联系人直接拨打电话

                if (ActivityCompat.checkSelfPermission(this, Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
                    // TODO: Consider calling
                    //    ActivityCompat#requestPermissions
                    // here to request the missing permissions, and then overriding
                    //   public void onRequestPermissionsResult(int requestCode, String[] permissions,
                    //                                          int[] grantResults)
                    // to handle the case where the user grants the permission. See the documentation
                    // for ActivityCompat#requestPermissions for more details.


                    return;

                }

                startActivity(intent);

            }
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

Answer 1

什么是“CONTENT_TYPE”？不应该是刚刚得到的电话串吗？

intent.setData(Uri.parse("tel:" + phone));

Answer 2

1. 在清单文件中添加权限：

2. 制作拨打电话号码的功能

   私有静态最终 int CALL_REQUEST = 100;

    private void callPhoneNumber(){
           if(Build.VERSION.SDK_INT >= Build.VERSION_CODES.M)
           {
               if (ActivityCompat.checkSelfPermission(this, Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
                  ActivityCompat.requestPermissions(ProfileActivity.this, new String[]{Manifest.permission.CALL_PHONE}, CALL_REQUEST);
   
                   return;
               }
           }
   
           Intent callIntent = new Intent(Intent.ACTION_CALL);
           callIntent.setData(Uri.parse("tel:9879879879" ));
           startActivity(callIntent);
   
       }
   

3. api level 23以上，调用时需要询问runtime权限，如果用户允许，会进入下面的方法：

   @覆盖 public void onRequestPermissionsResult(int requestCode, String[] 权限, int[] 授予结果） { 如果（请求代码 == CALL_REQUEST） { 如果（grantResults[0] == PackageManager.PERMISSION_GRANTED） { 电话号码（）； } 别的 { Toast.makeText(ProfileActivity.this, "权限被拒绝", Toast.LENGTH_SHORT).show(); } } }