Vb.net中两个日期之间的差异（0 YEAR，0 MONTHS，0 DAYS LEFT）[重复]答案

【问题标题】：Difference between two dates in Vb.net (0 YEAR, 0 MONTHS, 0 DAYS LEFT) [duplicate]Vb.net中两个日期之间的差异（0 YEAR，0 MONTHS，0 DAYS LEFT）[重复]
【发布时间】：2011-11-29 06:33:37
【问题描述】：

可能重复：
How to get difference between two dates in Year/Month/Week/Day?

我对两个日期之间的差异有疑问。我需要输出 0 YEAR, 0 MONTHS, 0 DAYS LEFTm 例如：

 1 YEAR, 2 MONTHS, 3 DAYS LEFT

使用 dateDiff 函数或使用其他任何东西是不可能的。

【问题讨论】：

标签： .net vb.net

【解决方案1】：

使用 DateTime 作为表示，你可以有类似的东西：

  dim test as DateTime = DateTime.Now
  dim test2 as DateTime = DateTime.Now.AddDays(2)
  dim result as TimeSpan = test.Subtract(test2)
  dim hours as Integer = result.Hours
  dim days as Integer = result.Days
  int years=days mod 365
  days=days-years*365

【讨论】：

【解决方案2】：

类似这样的：

    ' A Start date an end Date to test with
    Dim StartingDate As DateTime = DateTime.Now
    Dim TargetEndDate As DateTime = DateTime.Now.AddYears(1).AddDays(5).AddMinutes(45)

    ' Get the difference between the two dates, and Create a new Date containing just the total days
    Dim DifferenceBetweenDates As TimeSpan = TargetEndDate.Subtract(StartingDate)
    Dim DiffFromSystemDate As New DateTime(0, 0, DifferenceBetweenDates.TotalDays)

    ' Get the number of years, months and days left
    Dim NumberOfYears As Integer = DiffFromSystemDate.Year - 1
    Dim NumberOfMonths As Integer = DiffFromSystemDate.Month - 1
    Dim NumberOfDays As Integer = StartingDate.Day - DateTime.DaysInMonth(StartingDate.Year, StartingDate.Month)

    ' Build up the result string
    Dim Result As String = String.Format("{0} YEAR, {1} MONTHS, {3} DAYS LEFT", NumberOfYears, NumberOfMonths, NumberOfDays)

我还没编译
它不能完全工作（闰年和一年中的日子）

请参阅 JonSkeets 的重复帖子以获得更好的方法

【讨论】：

【解决方案3】：

我曾经遇到过同样的问题并找到了一个解决方案。请记住 d1 是 endDate，d2 是 startDate。 d1 > d2

public static void TimeSpanToDate(DateTime d1, DateTime d2, out int years, out int months, out int days)
{
    // compute & return the difference of two dates,
    // returning years, months & days
    // d1 should be the larger (newest) of the two dates
    // we want d1 to be the larger (newest) date
    // flip if we need to
    if (d1 < d2)
    {
        DateTime d3 = d2;
        d2 = d1;
        d1 = d3;
    }

    // compute difference in total months
    months = 12 * (d1.Year - d2.Year) + (d1.Month - d2.Month);

    // based upon the 'days',
    // adjust months & compute actual days difference
    if (d1.Day < d2.Day)
    {
        months--;
        days = DateTime.DaysInMonth(d2.Year, d2.Month) - d2.Day + d1.Day;
    }
    else
    {
        days = d1.Day - d2.Day;
    }
    // compute years & actual months
    years = months / 12;
    months -= years * 12;
}

对我来说很好用。

希望对你有帮助。

普雷文

【讨论】：