如何在 T-SQL 中找到给定时间间隔内的周数

Question

我有点卡在这里，我想在给定的时间间隔内找到所有周数，但我真的无法弄清楚

例如，而不是 - > datepart(week,dateadd(day,-1,@oneSingleDate))（星期一是一周的第一天），

我需要类似的东西

- > datepart(week,@startDate,@endDate) 

给定间隔'2019-01-04'-'2019-01-28'，输出需要是：

周号：1,2,3,4,5.

Answer 1

我使用递归 CTE 生成范围内的所有日期，然后使用 DATEPART 从它们中选择 DISTINCT 周数。然后我将 then 连接到您的逗号分隔字符串中，然后将其连接到一个名为 @OUT

的变量中

DECLARE @startDate as date = '20190104';
DECLARE @endDate as date = '2019-01-28';

DECLARE @OUT as nvarchar(max);

WITH CTE AS (SELECT @startDate As X
             UNION ALL
             SELECT DATEADD(y, 1, X) X FROM CTE where x < @endDate),
    CTE2 AS (SELECT DISTINCT datepart(wk, X) wk from cte)
    select @out = coalesce(@out + ', ', '') + cast(wk as nvarchar(4))  from cte2
    OPTION (MAXRECURSION 0);

    select @out;

Answer 2

你可以这样做： 使用 ： - [CTE][1] 常用表格表达式 - [Sql递归联合全部][2] - [多行拼接成一行][3]

declare @startDate as date ;
declare @endDate as date ;
set @startDate='2019-01-04'; 
set @endDate='2019-01-28' ;
DECLARE @weeks VARCHAR(8000) ;
with cte as (select @startDate as mydate,datepart(week,@startDate) w
union all select
dateadd(day,1,mydate),datepart(week,dateadd(day,1,mydate))  from cte
where mydate < @endDate) , cte2 as (select distinct(w) from cte)
select @weeks=COALESCE(@weeks + ', ', '') +cast(w as varchar(2)) from
cte2 OPTION (MAXRECURSION 360) select @weeks [Result]