PHP Mail() 函数在反馈表单中注入“@cp-in-3.webhostbox.net”和“发件人”地址

Question

通过反馈表发送邮件时，我遇到了很多问题。首先，该函数在本地主机中发送邮件。但上传到远程服务器后，它停止发送。无论如何，我以某种方式修复了。现在它正在发送邮件，但向“FROM”地址注入了更多字符串。请查看我编写的代码以及收到电子邮件后我收到的代码。

代码====>

<?php

    function putinplace($string=NULL, $put=NULL, $position=false)
    {
        $d1=$d2=$i=false;
        $d=array(strlen($string), strlen($put));
        if($position > $d[0]) $position=$d[0];
        for($i=$d[0]; $i >= $position; $i--) $string[$i+$d[1]]=$string[$i];
        for($i=0; $i<$d[1]; $i++) $string[$position+$i]=$put[$i];
        return $string;
    }

    $from1 = $_POST["email"];
    $from = preg_replace('/[^a-zA-Z0-9@\.]/', ' ', $from1);

    $at_pos = strpos($from, "@");

    $from = putinplace($from, "\\", $at_pos);

    $subject1 = $_POST["subject"];
    $subject = preg_replace('/[^a-zA-Z0-9\']/', ' ', $subject1);
    $message1 = $_POST["body"];
    $message = preg_replace('/[^a-zA-Z0-9\']/', ' ', $message1);
    $to = "emailidtosend@gmail.com";
    $headers = 'MIME-Version: 1.0' . "\r\n";
    $headers = 'From: abc.co.in' . "\r\n". 'Reply-To: emailidtosend@gmail.com' . "\r\n" .'X-Mailer: PHP/' . phpversion();
    $headers .= 'Content-type : text/html; CHARSET=ISO-8859-1' . "\r\n";
    $headers = "From:" . $from . "\r\n";

    if(mail($to,$subject,$message,$headers)){
        echo "<script>alert('Email Sent Successfully. We will Get back to you Very soon.');</script>";
        echo "<script>window.open('contact-us.php', '_self');</script>";
    }else{
        echo "<script>alert('Unable To Send The Email.');</script>";
        echo "<script>window.open('contact-us.php', '_self');</script>";
    }
?>

而输出===>

用户名\@gmail.com@cp-in-3.webhostbox.net（查看“FROM”地址的最后部分）

Answer 1

You do not need to put  via cp-in-9.webhostbox.net 
You need to configure you php.ini file in your web server.

Step 1. Find php.ini file
If it's not there then create one in home directory and add codes below

[mail function]
; For Win32 only.
SMTP = localhost
smtp_port = 25

; For Win32 only.
;sendmail_from = me@example.com

; For Unix only.  You may supply arguments as well (default: "sendmail -t -i").
;sendmail_path = /usr/sbin/sendmail

this path "/usr/sbin/sendmail" is specific to server.
To get yours just create a php file with code 
<?php
phpinfo();
?>

and hit that file from web browser you will get the path value for key sendmail_path

One small and simple example for sending email in php is as :

<?php

// Set up parameters
$to = "Vivek.kumar@xyz.com";
$subject = "Your password";
$message = "<p>Hello Homer,</p>
<p>Thanks for registering.</p>
<p>Your password is: <b>springfield</b></p>
";
$from = "vivek@domainname.com";

$headers = "MIME-Version: 1.0" . "\n";
$headers .= "Content-type:text/html;charset=iso-8859-1" . "\n";
$headers .= "From: $from" . "\n";

// Send email
mail($to,$subject,$message,$headers);

// Inform the user
echo "Thanks for registering! We have just sent you an email with your password.";

?>