龙卷风 RequestHandler 中的 Python AsyncHttpClient 抛出异常

Question

我将在RequestHandler中通过tornado AsyncHttpClient调用一个端点，但是它抛出了运行时异常This event loop is already running

class RegistrationHandler(tornado.web.RequestHandler):

  def post(self, *args, **kwargs):
      call_async_register("some params")


def call_async_register(parameters):
    def call():
        http_client = AsyncHTTPClient()
        future = Future()
        http_request = HTTPRequest(url, request_type.name, headers={'X-Peering': '1'}, body=body)

        def handle_future(f: Future):
            future.set_result(f.result())

        fetched_future = http_client.fetch(http_request)

        fetched_future.add_done_callback(handle_future)

        return future
    try:
        instance = io_loop.IOLoop.current()
        response = instance.run_sync(call)
        return response.body.decode()
    except Exception as err:
        self.logger.exception("Account Request Failed: {}".format(err))
        return None

Answer 1

问题来了：

instance = io_loop.IOLoop.current()
response = instance.run_sync(call)

run_sync 本身尝试启动 ioloop。但从您的代码中可以明显看出，instance 已经在运行。所以你得到了错误。

如果您想将call() 方法返回的值发送回用户，请将您的方法转换为协程（使用async/await 语法）。

例子：

class RegistrationHandler(tornado.web.RequestHandler):

    async def post(self, *args, **kwargs):
        response = await call_async_register("some params")

        self.write(response)


async def call_async_register(parameters):
    http_client = AsyncHTTPClient()
    http_request = HTTPRequest(url, request_type.name, headers={'X-Peering': '1'}, body=body)

    try:
        response = await http_client.fetch(http_request)
        return response.body.decode()
    except Exception as err:
        self.logger.exception("Account Request Failed: {}".format(err))
        return None