使用ajax成功提交表单后重新加载页面答案

【问题标题】：Reload a page after successfully submit a form using ajax使用ajax成功提交表单后重新加载页面
【发布时间】：2015-07-03 08:13:35
【问题描述】：

我目前正在使用 ajax 制作登录表单

<div id='error3'></div>
<input type='email' required name='email' id='email' placeholder='Email'>
<input type='password' required name='password' id='password' placeholder='password'>
<input type='submit'  name='submit99' id='submit' value='login'>

我的java脚本是

<script>
$(document).ready(function(){
    $("#submit").click(function(){
        var emailnew = $("#email").val();
        var  password = $("#password").val();

        var dataString = '&email='+ email + '&password='+ password;
        if(emailnew==''|| password='')
        {
            document.getElementById('error3').innerHTML="Please Fill All Fields";
        }
        else
        {
            $.ajax({
                type: "POST",
                url: "process.php",
                data: dataString,
                cache: false,
                success: function(result){
                    document.getElementById('error3').innerHTML=result;
                }

            });
        }
        return false;
    });
});

我的 process.php 脚本是

<?php
if(isset($_POST['email']))
{
    if (filter_var($email99, FILTER_VALIDATE_EMAIL))
    {
        $con=mysqli_connect('localhost','root','password','database');
        $query="SELECT * FROM TABLENAME WHERE USER='' AND PASSWORD=''";
        $result=mysqli_query($con,$query);
        if(mysqli_num_rows($result)!=0)
        {
            echo "You are successfully logged in";
login user
start a cookie or session
    }
        else
        {
            echo "You are bot a valid user";
        }
    }
    else
        echo "not a valid email";
}
?>

现在如果我们收到“您已成功登录”消息刷新当前页面，否则只显示错误消息并且不刷新页面。

我可以选择添加

<meta http-equiv="refresh" content="30">

但这仅适用于 chrome 而不是 Firefox。

【问题讨论】：

标签： php ajax asynchronous

【解决方案1】：

你可以把条件放在循环success: function(result){

<script>
    $(document).ready(function () {
        $("#submit").click(function () {
            var emailnew = $("#email").val();
            var password = $("#password").val();

            var dataString = '&email=' + email + '&password=' + password;
            if (emailnew == '' || password = '') {
                document.getElementById('error3').innerHTML = "Please Fill All Fields";
            } else {
                $.ajax({
                    type: "POST",
                    url: "process.php",
                    data: dataString,
                    cache: false,
                    success: function (result) {
                        if (result == "You are successfully logged in") {
                            document.location.href = 'login.htm';
                        } else {
                            document.getElementById('error3').innerHTML = result;
                        }
                    }

                });
            }
            return false;
        });
    });
</script>

【讨论】：

【解决方案2】：

试试这个：

<script>
    $(document).ready(function () {
        $("#submit").click(function () {
            var emailnew = $("#email").val();
            var password = $("#password").val();

            var dataString = '&email=' + email + '&password=' + password;
            if (emailnew == '' || password = '') {
                document.getElementById('error3').innerHTML = "Please Fill All Fields";
            }
            else {
                $.ajax({
                    type: "POST",
                    url: "process.php",
                    data: dataString,
                    cache: false,
                    success: function (result) {
                        document.getElementById('error3').innerHTML = result;
                        if (result == "You are bot a valid user") {
                            window.location.href = "mypage.html"
                        }
                    }

                });
            }
            return false;
        });
    });
</script>

【讨论】：

【解决方案3】：

<script>
    $(document).ready(function(){
        $("#submit").click(function(){
            var emailnew = $("#email").val();
            var  password = $("#password").val();

            var dataString = '&email='+ email + '&password='+ password;
            if(emailnew == null || password == null)
            {
                document.getElementById('error3').innerHTML="Please Fill All Fields";
            }
            else
            {
                $.ajax({
                    type: "POST",
                    url: "process.php",
                    data: dataString,
                    cache: false,
                    success: function(result)
                    {
                        if(result == "logged in true")
                        {
                            window.setTimeout(function(){location.reload()},1000); //reload with time
                            location.reload(); //reload without time
                        }
                        else
                        {
                            document.getElementById('error3').innerHTML=result;
                        }


                    }

                });
            }
            return false;
        });
    });
</script>

【讨论】：

【解决方案4】：

您的 process.php 应该返回一个结果，如成功 (true) 和不成功 (false) 标志。或用户ID，例如，如果它成功，则其他一些标志，如果它不是。您不应该在您的 proccess.php 文件中回显通知。那么你可以在你的 javascript 代码中有这样的东西：

$.ajax({
   type: "POST",
   url: "process.php",
   data: dataString,  
   cache: false,
   success: function(result){
      if(result=='successful'){
          showMessageAndredirectFunction();
          //in this functionyou can show the message in your html page like the way you do for error and with a delay redirect the page with javascript
      else
        document.getElementById('error3').innerHTML="Bad usernaem or password";
   }});

如果会话成功，您可以在 process.php 中设置会话。

【讨论】：

【解决方案5】：

window.location.reload() 用于使用 javascript 重新加载页面。或者你可以使用window.location.href=window.location.href;

【讨论】：