Restful Services org.netbeans.rest.application.config.Application Config 抛出异常

Question

我有一个 Angular 客户端；其将数据发布到 java Rest Api。当我尝试发送字符串或整数数据时，没有任何问题。但是当我尝试发送 List 时，它给出了一个类似的错误；enter image description here

StandardWrapperValve[org.netbeans.rest.application.config.ApplicationConfig]：Servlet org.netbeans.rest.application.config.ApplicationConfig 的 Servlet.service() 抛出异常 java.lang.IllegalArgumentException：参数类型不匹配

还有我的 Java Api

@POST
@Path("/senddata")
@Produces("application/json")
public String sendData(List<Data> model) throws Exception {
    System.out.println("model : " + model);

    return "OK";
}

来自 Angularjs 的请求

   return $http.post('http://localhost:8080/Project/webresources/json/product/senddata', postData1, {
      headers: { 'Content-Type': 'application/json' }
    });

我的字符编码类

@WebFilter("*.xhtml")
public class CharacterEncodingFilter implements Filter {

    @Override
    public void init(FilterConfig config) throws ServletException {
    }

    @Override
    public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
        request.getCharacterEncoding();
        response.getCharacterEncoding();
        request.setCharacterEncoding("UTF-8");
        response.setCharacterEncoding("UTF-8");
        response.setContentType("text/html; charset=UTF-8");
        chain.doFilter(request, response);
    }

    @Override
    public void destroy() {
    }
}

谢谢

Answer 1

您可以尝试为您的 List 创建一个包装器对象并在您的参数列表中使用它；

public class DataWrapper { 
    private List<Data> dataList;
...
}  


@POST
@Path("/senddata")
@Produces("application/json")
public String sendData(DataWrapper data) throws Exception {
...

或者将@RequestParam(value="model") 注释添加到您现有的参数中。

public String sendData(@RequestParam(value="model") List<Data> model) throws Exception