寻找最多两位小数的正则表达式答案

【问题标题】：Looking for a REGEXP for a number upto two decimal places寻找最多两位小数的正则表达式
【发布时间】：2014-05-07 18:09:40
【问题描述】：

我正在尝试这个

/-?(?:\d+|\d{1,3}(?:,\d{3})+)?(?:\.\d+)?$/

但这需要多于两位小数，并且它接受值“.00”

它应该接受以下值
100.00
00.00
0
100
10000000000.00
98173827827.82

它应该拒绝以下值 .00
10.098
87.89381938193819
9183983109.9283912
10.aa
adjbdjbdj

我是正则表达式的新手

PS：- 我正在尝试下面的 javascript 代码。因此，请将表达式仅限于 javascript。

提前致谢

【问题讨论】：

标签： javascript jquery regex pattern-matching

【解决方案1】：

这个应该做的：

/^\d+(\.\d{1,2})?$/

【讨论】：

用于测试和很好的可视化这个正则表达式的作用 - debuggex

【解决方案2】：

我会这样做：

/-?(?:\d{1,3}(?:,?\d{3})+)?(?:\.\d{1,2})?$/

【讨论】：

【解决方案3】：

试试这个：

if (/^\d+([,.]\d{1,2})?$/im.test(value)) {
        alert("ACCEPTED\n" + value);
    } else {
        alert("REJECTED\n" + value);
    }
}

JSFIDDLE EXAMPLE

正则表达式解释

^\d+([,.]\d{1,2})?$

Assert position at the beginning of a line (at beginning of the string or after a line break character) (line feed, line feed, line separator, paragraph separator) «^»
Match a single character that is a “digit” (ASCII 0–9 only) «\d+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the regex below and capture its match into backreference number 1 «([,.]\d{1,2})?»
   Between zero and one times, as many times as possible, giving back as needed (greedy) «?»
   Match a single character from the list “,.” «[,.]»
   Match a single character that is a “digit” (ASCII 0–9 only) «\d{1,2}»
      Between one and 2 times, as many times as possible, giving back as needed (greedy) «{1,2}»
Assert position at the end of a line (at the end of the string or before a line break character) (line feed, line feed, line separator, paragraph separator) «$»

【讨论】：