【发布时间】:2009-12-02 16:15:29
【问题描述】:
我正在编写一个简单的小 ocaml 程序,它从文件中读取代数语句,使用 ocamllex/ocamlyacc 将其解析为 AST,对其进行缩减,然后将其打印出来。我减少表达的部分似乎有点……丑陋。有什么办法可以简化吗?
(* ocaml doesn't seem to be able to take arithmetic operators
as functions, so define these wrappers for them *)
let add x y =
x + y
let sub x y =
x - y
let mul x y =
x * y
let div x y =
x / y
(* Are term1 and term2 both ints? *)
let both_ints term1 term2 =
match (term1, term2) with
| (Term (Number x), Term (Number y)) -> true
| (_, _) -> false
(* We know that both terms are reducable to numbers, so combine
them *)
let combine_terms func x y =
match (x, y) with
(Term (Number t1), Term (Number t2)) ->
(Term (Number (func t1 t2)))
| (_, _) -> raise InvalidArg
(* Reduce the expression as much as possible *)
let rec reduce_expr expr =
match expr with
Plus (x, y) ->
let reduced_x = reduce_expr x
and reduced_y = reduce_expr y in
if both_ints reduced_x reduced_y then
(combine_terms add reduced_x reduced_y)
else
Plus (reduced_x, reduced_y)
| Minus (x, y) ->
let reduced_x = reduce_expr x
and reduced_y = reduce_expr y in
if both_ints reduced_x reduced_y then
(combine_terms sub reduced_x reduced_y)
else
Minus (reduced_x, reduced_y)
| Multiply (x, y) ->
let reduced_x = reduce_expr x
and reduced_y = reduce_expr y in
if both_ints reduced_x reduced_y then
(combine_terms mul reduced_x reduced_y)
else
Multiply (reduced_x, reduced_y)
| Divide (x, y) ->
let reduced_x = reduce_expr x
and reduced_y = reduce_expr y in
if both_ints reduced_x reduced_y then
(combine_terms div reduced_x reduced_y)
else
Divide (reduced_x, reduced_y)
| Term x -> Term x
【问题讨论】:
-
请注意,ocaml 确实将算术运算符作为函数:使用 ( / )、( + ) ( * ) 和 ( - )... () 是必需的,空格仅对 *
-
只是为了解析,menhir 值得考虑。 cristal.inria.fr/~fpottier/menhir
-
其实我一直在使用 ocamlyacc 并且我通常会使用 menhir,但我想保持简单的依赖关系。
标签: refactoring pattern-matching ocaml