用星号python分割字符串

Question

我2天前刚开始学习python，如果我犯了明显的错误，请见谅

strings: "brake  break  at * time" --> ["at","time"]
"strang  strange  I felt very *" --> ["very",""]

我想在 * 之前和之后得到消息

我的尝试：

re.match(r"(?P(first_word)\w+) ('_*_') (?P(first_word)\w+)",strings).group('first_word')

获取第一个单词

re.match(r"(?P(first_word)\w+) ('_*_') (?P(first_word)\w+)",strings).group('last_word')

最后一个字

错误：无需重复

Answer 1

只需使用string.split('*')。

像这样（仅适用于 1 *）：

>>> s = "brake  break  at * time"
>>> def my_func(s):
     parts = s.split('*')
     a = parts[0].split()[-1]
     b = parts[1].split()[0] if parts[1].split() else ''
     return a,b
>>> my_func(s)
('at', ' time')

或者如果你想要正则表达式：

>>> s = "brake  break  at * time 123 * blah"
>>> regex = re.compile("(\w+)\s+\*\s*(\w*)")
# Run findall
>>> regex.findall(s)
[(u'at', u'time'), (u'123', u'blah')]

Answer 2

import re
text1 = "brake  break  at * time"
text2 = "strang  strange  I felt very *"
compiled = re.compile(r'''
(\w+)  # one or more characters from [_0-9a-zA-Z] saved in group 1
\s+  # one or more spaces
\*  # literal *
\s*  # zero or more spaces
(\w*)  # zero or more characters from [_0-9a-zA-Z] saved in group 2
''',re.VERBOSE)

def parse(text):
    result = compiled.search(text)
    return [result.group(1), result.group(2)]

print(parse(text1))
print(parse(text2))

输出：

['at', 'time']
['very', '']

Answer 3

试试：

[x.strip() for x in "test1 * test2".split('*', 1)]

.strip() 去掉空格，.split('*', 1) 用星号分割字符串一次。

你只要一个字：

words = [x.strip() for x in "test1 * test2".split('*', 1)]
first = words[0].rsplit(' ', 1)[1]
last = words[1].split(' ', 1)[0]