无法在 Google Maps API 调用中获取点

Question

我使用 Google Maps API 渲染了以下 HTML 页面。这已经运行了大约两个月，突然停止工作。我试图用 getLatLng 函数来理解这一点，它似乎每次都返回 null。有没有人遇到过类似的问题或在这里看到任何问题？任何帮助表示赞赏。

使用 API 版本 2。 ("v=2")

var map = null;
var geocoder = null;
var marker;
var g_address = "1 Yawkey Way Boston MA";
var toggleState = 0;
var toggleStateDir = 0;

var mapDir;
var gDir;
var geocoderDir = null;
var markerDir;
var g_addressDir = "100 Commonwealth Ave Boston MA";

var panorama;
var currentYaw = 180;
var currentPitch = 0;
var currentZoom = 0;

function initialize() 
{
    if (GBrowserIsCompatible()) 
    {
        // Map                        
        document.getElementById("address").value = g_address;
        document.getElementById("addressDir").value = g_addressDir;
        map = new GMap2(document.getElementById("map_canvas"));
        map.addControl(new GMapTypeControl());
        map.addControl(new GScaleControl());
        map.addControl(new GLargeMapControl3D());

        // Street View
        geocoder = new GClientGeocoder();
        panorama = new GStreetviewPanorama(document.getElementById("pano"));

        // Directions
        mapDir = new GMap2(document.getElementById("map_canvas_dir"));
        gDir = new GDirections(mapDir, document.getElementById("directions"));
        mapDir.addControl(new GMapTypeControl());
        mapDir.addControl(new GScaleControl());
        mapDir.addControl(new GLargeMapControl3D());

        // Traffic overlay
        map.setUIToDefault();
        var trafficOptions = { incidents: true };
        trafficInfo = new GTrafficOverlay(trafficOptions);
        mapDir.setUIToDefault();
        var trafficOptionsDir = { incidents: true };
        trafficInfoDir = new GTrafficOverlay(trafficOptionsDir);

        showAddress(g_address, g_addressDir);
    }
}

function showAddress(address, addressDir) 
{
    if (geocoder)
    {
        geocoder.getLatLng(address,
            function(point) {
                if (!point) {
                    alert(address + " not found" + response.Status.code);
                }
                else {
                    // Map                        
                    g_address = address
                    map.setCenter(point, 15);
                    marker = new GMarker(point);
                    map.addOverlay(marker);
                    // Street View
                    document.getElementById("lat").value = point.y;
                    document.getElementById("long").value = point.x;
                    document.getElementById("pano").removeAttribute("pano");
                    panorama.setLocationAndPOV(new GLatLng(point.y, point.x), { yaw: currentYaw, pitch: currentPitch, zoom: currentZoom });
                    // Directions
                    gDir.load("from: " + addressDir + " to: " + address, { "locale": "en_US" });
                }
            }
        );
    }
}

Answer 1

该代码没有任何问题。它非常适合我。

很遗憾，.getLatLng() 失败时不会返回错误码，而当 .getLatLng 什么都不返回时，此行会崩溃：

alert(address + " not found" + response.Status.code);

我无法猜测您的 API 密钥是否存在问题（错误 610），或者您是否因发出过多地理编码请求而被阻止（错误 620）。我强烈怀疑它将是这两者之一，因为任何其他错误代码都会在我尝试时导致代码失败。

尝试将您的 (!point) 代码更改为

if (!point) {
   geocoder.getLocations(address, function(response) {
     alert(address + " not found: " + response.Status.code);
   });
}

在同一地址上使用 .getLocations() 并显示错误代码。