【发布时间】:2018-05-22 09:12:39
【问题描述】:
所以,我有一个可自行更新的 .csv 文件。我想用它做一些事情,不知道如何处理它,希望你能帮助我。 csv 中的数据如下所示: 没有标题。我也可以在没有分隔符的情况下将日期和时间加入同一列。
07/12/2017,23:50,113.179,113.182,113.168,113.180,113.187,113.189,113.176,113.186,144
07/12/2017,23:51,113.180,113.190,113.180,113.187,113.186,113.196,113.186,113.193,175
07/12/2017,23:52,113.187,113.188,113.174,113.186,113.193,113.194,113.181,113.192,340
07/12/2017,23:53,113.186,113.192,113.175,113.181,113.192,113.199,113.182,113.188,282
07/12/2017,23:54,113.181,113.183,113.170,113.171,113.188,113.188,113.176,113.179,74
07/12/2017,23:55,113.171,113.181,113.170,113.179,113.179,113.188,113.176,113.186,329
07/12/2017,23:56,113.179,113.189,113.174,113.181,113.186,113.195,113.181,113.187,148
07/12/2017,23:57,113.181,113.181,113.169,113.169,113.187,113.187,113.175,113.175,55
07/12/2017,23:58,113.169,113.183,113.169,113.182,113.175,113.188,113.175,113.187,246
07/12/2017,23:59,113.182,113.210,113.175,113.203,113.187,113.215,113.181,113.209,378
08/12/2017,00:00,113.203,113.213,113.180,113.183,113.209,113.220,113.187,113.190,651
08/12/2017,00:01,113.183,113.190,113.164,113.167,113.190,113.196,113.171,113.174,333
08/12/2017,00:02,113.167,113.182,113.156,113.156,113.174,113.188,113.162,113.163,265
08/12/2017,00:03,113.156,113.165,113.151,113.163,113.163,113.172,113.158,113.170,222
08/12/2017,00:04,113.163,113.163,113.154,113.159,113.170,113.170,113.159,113.166,148
08/12/2017,00:05,113.159,113.163,113.153,113.154,113.166,113.168,113.159,113.162,162
对于初学者,我有兴趣在此练习中仅使用前两列(如果日期和时间分开,则使用前两列)。比如:
07/12/2017,21:54,113.098
07/12/2017,21:55,113.096
07/12/2017,21:56,113.087
07/12/2017,21:57,113.075
07/12/2017,21:58,113.087
07/12/2017,21:59,113.079
每隔一秒左右就会添加新的行,其中包含更新的日期时间。 我可以做类似的事情
df = pd.read_csv("C:\\Users\\xxx\\Desktop\\csvexport\\thefile.csv")
print(df[-1:])
查看数据帧的最后一行(尾部)
现在,我无法执行以下操作,感谢您的帮助:
更新数据框,以便我可以使用最新版本来计算新行何时出现(不使用睡眠计时器?)
能够绘制数据,新数据到达时会自动反映新更新的数据(x 轴上的日期时间,y 轴上的浮点数)
我在生成 .csv 文件的程序的命令窗口中看到的输出是这样的,如果这很重要的话
asset 08/12/2017 05:16:37 float:113.336 floattwo:113.328 digit:20
asset 08/12/2017 05:16:40 float:113.334 floattwo:113.328 digit:21
asset 08/12/2017 05:16:40 float:113.335 floattwo:113.323 digit:22
asset 08/12/2017 05:16:41 float:113.331 floattwo:113.328 digit:23
asset 08/12/2017 05:16:43 float:113.334 floattwo:113.327 digit:24
asset 08/12/2017 05:16:47 float:113.332 floattwo:113.328 digit:25
因此您可以看到更新并不完全相隔一秒,它们可能存在间隙,有时也可能在同一秒内发生(05:16:40 两次)
因此,我希望将情节保持在相同的时间间隔(1 分钟或 5 分钟等),但根据属于该分钟的 .csv 中的浮动值不断更改最近的点.当下一分钟的一行到达时,只有这样情节才能向右移动(但随着浮点数的变化而不断波动)......希望你明白这一点。我想用 pyqtgraph 作图。
我设法编写了这么多代码......但这不是最好的例子,对不起。当然,情节并不是这样的。只是说明我想看到的。所以绿条应该不断改变值,直到下一个时间步被添加到 csv
import pyqtgraph as pg
from pyqtgraph import QtCore, QtGui
import pandas as pd
import datetime
x = pd.read_csv("C:\\Users\\xxx\\Desktop\\csvexport\\thefile.csv")
z = x[-1:]
def getlastrow():
for a in z.iterrows():
d = ((int(((a[1][0]).split("/")[0]))))
m = ((int(((a[1][0]).split("/")[1]))))
y = ((int(((a[1][0]).split("/")[2]))))
hh = ((int(((a[1][1]).split(":")[0]))))
mm = ((int(((a[1][1]).split(":")[1]))))
#ss = ((int(((a[1][1]).split(":")[2]))))
thedate = datetime.date(y, m, d)
thetime = datetime.time(hh, mm)
p = (a[1][2])
return ((thedate,thetime,p))
# print(str(getlastrow()[0]).replace("-",""))
# print(getlastrow()[1])
# print(getlastrow()[2])
class CandlestickItem(pg.GraphicsObject):
def __init__(self):
pg.GraphicsObject.__init__(self)
self.flagHasData = False
def set_data(self, data):
self.data = data
self.flagHasData = True
self.generatePicture()
self.informViewBoundsChanged()
def generatePicture(self):
self.picture = QtGui.QPicture()
p = QtGui.QPainter(self.picture)
p.setPen(pg.mkPen('w'))
w = (self.data[1][0] - self.data[0][0]) / 2.
for (t, open) in self.data:
p.drawLine(QtCore.QPointF(t, open), QtCore.QPointF(t, open))
p.setBrush(pg.mkBrush('r'))
if open > 122.8:
p.setBrush(pg.mkBrush('g'))
p.drawRect(QtCore.QRectF(t-w, open, w*2, open))
p.end()
def paint(self, p, *args):
if self.flagHasData:
p.drawPicture(0, 0, self.picture)
def boundingRect(self):
return QtCore.QRectF(self.picture.boundingRect())
app = QtGui.QApplication([])
data = [
[(int(str(getlastrow()[0]).replace("-",""))), (getlastrow()[2])],
[(int(str(getlastrow()[0]).replace("-","")))+1, (getlastrow()[2])+0.1],
[(int(str(getlastrow()[0]).replace("-","")))+2, (getlastrow()[2])+0.2],
]
item = CandlestickItem()
item.set_data(data)
plt = pg.plot()
plt.addItem(item)
plt.setWindowTitle('pyqtgraph example: customGraphicsItem')
def update():
global item, data
new_bar = (int(str(getlastrow()[0]).replace("-","")))+3, ((getlastrow()[2])+10)
data.append(new_bar)
item.set_data(data)
app.processEvents()
timer = QtCore.QTimer()
timer.timeout.connect(update)
timer.start(100)
if __name__ == '__main__':
import sys
if (sys.flags.interactive != 1) or not hasattr(QtCore, 'PYQT_VERSION'):
QtGui.QApplication.instance().exec_()
【问题讨论】:
-
为什么要把它写到平面文件中?而是使用数据库
-
哦,这是另一天的大话题。我正在读这个。 quant.stackexchange.com/questions/29572/…
-
不,这不是写入和使用数据的方式。与平面文件相比,数据库提供了更多功能。
-
这可以成为解决方案之一
标签: python pandas plot real-time pyqtgraph