【发布时间】:2017-11-14 15:12:35
【问题描述】:
我有两个动作类
public class TokenAction extends Action {
private ActionForward getToken(ActionMapping actionMapping, ActionForm actionForm, HttpServletRequest request,
HttpServletResponse response) throws IOException {
String token = generateToken();
response.setContentType("text/plain");
response.getWriter().print(token);
return null;
}
和
public class ActionTwo extends Action{
private ActionForward doSomething(ActionMapping actionMapping, ActionForm actionForm, HttpServletRequest request,
HttpServletResponse response) {
token = ???
return actionMapping.findForward("page");
}
}
如何从 TokenAction 进入 ActionTwo?
【问题讨论】: