频率未累加 (SAS PROC SQL)

Question

我正在尝试仅查找唯一 ID 号的频率。我尝试了 PROC FREQ，但无法弄清楚如何执行 SELECT DISTINCT 的 SAS 等效项。我运行了以下代码并得到了不相加的数字。

代码： PROC SQL; SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n;

结果： 20599

代码：

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '1a (obs): Demonstrating knowledge of content and pedagogy';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '1a (p&p): Demonstrating knowledge of content and pedagogy';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '1e (obs): Designing coherent instruction';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '1e (p&p): Designing coherent instruction';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '2a: Creating an environment of respect and rapport';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '2d: Managing student behavior';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '3b: Using questioning and discussion techniques';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '3c: Engaging students in learning';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '3d: Using assessment in instruction';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '4e (obs): Growing and developing     professionally';

PROC SQL;
SELECT COUNT (DISTINCT MOTPID) FROM WORK.'0__1_MOTP_COMMENTS_0000'n
WHERE MOTPComponentDescription = '4e (p&p): Growing and developing professionally';

在此处查看数据集的 sn-p：https://docs.google.com/spreadsheets/d/1WDcsezb4xiT67J9t3Nlyi_QEofs0dhyZ23yC32ccbqg/edit?usp=sharing

结果： 1a（obs）：展示内容和教学法知识：700

1a (p&p)：展示内容和教学法知识：606

1e (obs)：设计连贯指令：15622

1e (p&p)：设计连贯指令：1135

2a：创​​造尊重和融洽的环境：2466

2d：管理学生行为：1005

3b：使用提问和讨论技巧：808

3c：让学生参与学习：2516

3d：在教学中使用评估：3058

4e (obs)：专业成长和发展：5245

4e (p&p)：专业成长和发展：588

总和 = 33746

33746 != 20599

寻找关于哪里出了问题的任何想法，或者是否有更好的方法来获得我想要的结果（MOTPCopmponentDescription 的唯一 MOTPID 的计数。提前非常感谢！

Answer 1

要在 StackOverflow 上讨论 SAS 问题，SASHELP 库上的示例数据非常方便。让我们使用 CARS 数据集。;

title "你看到的问题没问题";

title2 "计算所有品牌";

proc sql;
    select count (distinct Make) as distinct_makes from sashelp.cars;
quit;

• 给 38;

title2“计算生产具有一定数量气缸的汽车的品牌”；

proc sql;
    select 'n.a.' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = . union
    select ' 3  ' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = 3 union
    select ' 4  ' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = 4 union
    select ' 5  ' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = 5 union
    select ' 6  ' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = 6 union
    select ' 8  ' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = 8 union
    select '10  ' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = 10 union
    select '12  ' as Cylinders, count (distinct Make) as distinct_makes from sashelp.cars where Cylinders = 12;
quit;

• 给出 1 个生产 3 个气缸，26 个生产 4 个气缸等等，“加起来”超过 80 个；

title2 "您可以手动验证这些列表中的结果";

proc sql;
    select Cylinders, Make, Model from sashelp.cars order by Cylinders, Make;
    select Make, Cylinders, Model from sashelp.cars order by Make, Cylinders;
quit;

title "你所谓的解决方案会产生不可预知的结果";

title2 "如果输入以一种方式排序，它会产生这个结果";

proc sort data=sashelp.cars out=cars_short2long;
    by length;
run;
proc sort data=cars_short2long nodupkey out=cars_short2long_clean dupout=dups;
    by Make;
run;
proc freq data=cars_short2long_clean;
    table Cylinders;
run;

• 表示没有人会制造 10 缸汽车；

title2 "如果输入以另一种方式排序，它会产生这个结果";

proc sort data=sashelp.cars out=cars_long2short;
    by descending length;
run;
proc sort data=cars_long2short nodupkey out=cars_long2short_clean dupout=dups;
    by Make;
run;
proc freq data=cars_long2short_clean;
    table Cylinders;
run;

• 表示没有人会制造 3 缸汽车；

Answer 2

这是我制定的解决方案，得到了我正在寻找的确切结果：

data comment_analysis;
set WORK.'0__1_MOTP_COMMENTS_0001'n;
run;

proc sort data=comment_analysis nodupkey out=comment_analysis_clean dupout=dups;
by motpid;
run;

proc freq data=comment_analysis_clean;
table MOTPComponentDescription;
run;

这是我正在寻找的输出： MOTPComponentDescription 频率百分比

1a (obs)：展示内容和教学法知识 520 2.52%

1a (p&p)：展示内容和教学法知识 400 1.94%

1e (obs)：设计连贯指令 11423 55.45%

1e (p&p)：设计连贯的指令 526 2.55%

2a：创​​造尊重和融洽的环境 1629 7.91%

2d：管理学生行为 556 2.70%

3b：使用提问和讨论技巧 563 2.73%

3c：让学生参与学习 1593 7.73%

3d：在指令 1818 中使用评估 8.83%

4e (obs)：专业成长和发展 1235 6%

4e (p&p)：专业成长和发展 336 1.64%