laravel 4 嘲弄模拟模型关系答案

【问题标题】：laravel 4 mockery mock model relationshipslaravel 4 嘲弄模拟模型关系
【发布时间】：2014-01-29 18:53:46
【问题描述】：

假设我有两个从 Eloquent 扩展而来的模型，它们相互关联。我可以嘲笑这段关系吗？

即：

class Track extends Eloquent {
    public function courses()
    {
        return $this->hasMany('Course');
    }
}

class Course extends Eloquent {
    public function track()
    {
        return $this->belongsTo('Track');
    }
}

在 MyTest 中，我当然想创建一个 mock，并返回一个 track 实例，通过调用 track 属性，而不是 track 实例（我不想要查询建设者)

use \Mockery as m;

class MyTest extends TestCase {
    public function setUp()
    {
        $track = new Track(array('title' => 'foo'));
        $course = m::mock('Course[track]', array('track' => $track));

        $track = $course->track  // <-- This should return my track object
    }
}

【问题讨论】：

标签： unit-testing laravel mocking laravel-4 mockery

【解决方案1】：

由于 track 是属性而非方法，因此在创建模拟时，您需要覆盖模型的 setAttribute 和 getAttribute 方法。下面是一个解决方案，可让您为您正在寻找的财产设定期望：

$track = new Track(array('title' => 'foo'));
$course = m::mock('Course[setAttribute,getAttribute]');
// You don't really care what's returned from setAttribute
$course->shouldReceive('setAttribute');
// But tell getAttribute to return $track whenever 'track' is passed in
$course->shouldReceive('getAttribute')->with('track')->andReturn($track);

在模拟Course 对象时，您不需要指定track 方法，除非您还想测试依赖于查询生成器的代码。如果是这种情况，那么您可以像这样模拟 track 方法：

// This is just a bare mock object that will return your track back
// whenever you ask for anything. Replace 'get' with whatever method 
// your code uses to access the relationship (e.g. 'first')
$relationship = m::mock();
$relationship->shouldReceive('get')->andReturn([ $track ]);

$course = m::mock('Course[track]');
$course->shouldReceive('track')->andReturn($relationship);

【讨论】：