Python 猜数游戏需要帮助避免在“猜数”中计算重复答案

【问题标题】：Python Number Guessing Game Need Help Avoiding Counting Duplicates in "Number of Guesses"Python 猜数游戏需要帮助避免在“猜数”中计算重复
【发布时间】：2015-12-19 00:55:52
【问题描述】：

我是学习 Python 的新手，正在构建一个非常简单的猜数游戏。用户猜测一个介于 1-100 之间的数字，并给出他们的猜测是太低还是太高的反馈。当他们猜对了数字时，程序会告诉他们猜了多少次。我需要帮助：告诉用户他们猜到了重复的数字（如果他们已经输入了）。我还想从最终猜测计数中排除任何重复的猜测。最简单的方法是什么？

这是我目前的游戏：

import random

print("Guess a number between 1-100")

the_number = random.randint(1, 100)
guess = int(input(""))
tries = 0

while guess != the_number:
    if guess > the_number:
        print("Lower")
    if guess < the_number:
        print("Higher")

    guess = int(input("Guess again: "))
    tries += 1
    if guess == the_number:
        print("You win! The number was", the_number)
        print("And it only took you", tries, "tries!\n")

【问题讨论】：

你知道，如果他们在第一次尝试时猜对了，它就永远不会进入循环，所以他们永远不会看到“你赢”的打印，对吧？至于如何按照您的要求进行操作，您必须跟踪他们在list 甚至更好的set 中所做的所有猜测，这样它就会为您“挤压”重复项。然后检查猜测是否已经在列表中

标签： python

【解决方案1】：

跟踪猜中的数字，仅当用户尚未猜中我们猜中的数字时才会增加：

import random

print("Guess a number between 1-100")

the_number = random.randint(1, 100)
tries = 0
# store all the user guesses
guessed = set()

while True:
    guess = int(input("Guess a number: "))
    # if the guess is in our guesses set, the user has guessed before
    if guess in guessed:
        print("You already guessed that number!")
        continue
    # will only increment for unique guessed
    tries += 1
    if guess == the_number:
        print("You win! The number was", the_number)
        print("And it only took you", tries, "tries!\n")
        break
    elif guess > the_number:
        print("Lower")
    # if it's not == or >, it has to be <
    else:
        print("Higher")
    # add guess each time
    guessed.add(guess)

您还对您的排序有一些逻辑，例如在循环之外进行猜测，这可能意味着如果用户第一次猜测，您就永远不会进入循环。

【讨论】：

【解决方案2】：

这就是你应该如何编写代码。

import random

debug = True


def number_guessing():
    previous_guesses = set()
    tries = 0
    print("Guess a number between 1-100")
    random_number = random.randint(1, 100)
    while True:
        guess = int(input())
        if guess in previous_guesses:
            print("You already tried that number")
            continue
        previous_guesses.add(guess)
        tries += 1

        if random_number < guess:
            print(f"Lower => previous attempts [{previous_guesses}] tries [{tries}]") if debug is True else None
        elif random_number > guess:
            print(f"Higher => previous attempts [{previous_guesses}] tries [{tries}]") if debug is True else None
        elif guess == random_number:
            print("You win! The number was", random_number)
            print(f"And it only took you {tries} attempt{'s' if tries>1 else ''}!\n")
            break


number_guessing()

【讨论】：