在循环中进行尝试和除外

Question

您好，我正在尝试弄清楚如何在 while 循环中放置“尝试并排除”。我的兄弟挑战我创建一个计算机程序，创建一个随机数（1-100），然后用户尝试猜测它是什么。我设法让它工作，但如果用户实际上没有输入数字，我应该做些什么，这样程序不仅会停止工作，而且只会提示用户他们做错了什么。下面我附上了我的完整代码。该程序有效，但我不确定如何将 While 循环放入其中。我尝试过做类似“猜猜！=整数”之类的事情，并且我一直在寻找不同的方法来了解如何做到这一点。我见过的最好的是有人只是说将 try 和 except 放入一个 while 循环中，但它并没有告诉我我该怎么做。 try-except inside a loop 。如果可能的话，我还想知道是否无论如何我都可以在用户回答时随时调用这个循环，所以如果他们不断地输入错误，我不需要做任何其他事情。感谢您花时间阅读本文，对不起，我写了很多

import random
import time
def guessMyNumber():
print("Hello , welcome to Guess My Number")
time.sleep(1)
print ("The computer is thinking of a number between 1-100")
time.sleep(2)
print("Try to guess the number in as few attempts as possible")
number=random.randint(1,100)
try:
    guess=int(input("Take a guess "))
except ValueError:
    print("You must enter a whole number")
    guess=int(input("Please take another guess, making sure that it is a whole number. Thank you. "))
 tries = 1
while guess !=number:
    if guess>number:
        print("You need to go lower")
        guess=int(input("Take a guess "))
    else:
        print("Go higher!")
        guess=int(input("Take a guess "))
    tries=tries+1
if tries < 5:
    print("Well done! You guessed the number in", tries, "tries! If you would like to play again please type 'guessMyNumber()'")
else:
        print("You guessed the number in", tries, "tries. If you would like to play again type 'guessMyNumber()' ")

guessMyNumber()

Answer 1

您的 except 块不应引发异常，下面是一个示例，您可以如何执行 int 并且您可以根据您的程序要求进行修改

count = 0
while count < 5:
 try:
    guess=int(input("Take a guess "))
 except ValueError:
    print("You must enter a whole number")
    print("Please take another guess, making sure that it is a whole number. Thank you. ")
 count = count+1