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Question

我有这段代码，但我似乎无法让它工作。当我运行它时，除非我手动杀死它，否则脚本不会在 IDLE 中完成。我已经翻遍并重写了几次代码，但没有运气。

import smtplib

SMTP_SERVER = 'smtp.gmail.com'
SMTP_PORT = 587

sender = 'abc@gmail.com'
password = '123'
recipient = 'cba@gmail.com'
subject = 'Test Results'
body = """** AUTOMATED EMAIL ** \r\n Following are
            the test results:  \r\n"""

headers = ["From: " + sender,
           "Subject: " + subject,
           "To: " + recipient]
headers = "\r\n".join(headers)

try:
      session = smtplib.SMTP(SMTP_SERVER, SMTP_PORT)
      session.ehlo()
      session.starttls()
      session.ehlo()
      session.login(sender, password)
      session.sendmail(sender, recipient, headers + "\r\n\r\n" + body)
except smtplib.SMTPException:
      print "Error: Unable to send email."

session.quit()

Answer 1

不知道你为什么使用ehlo；与流行的观点相反，只要您正确设置标题，它实际上并不是必需的。这是一个经过测试和工作的脚本——它适用于 *nix 和 OSX。由于您使用的是 Windows，因此我们需要进一步排除故障。

import smtplib, sys

def notify(fromname, fromemail, toname, toemail, subject, body, password):
    fromaddr = fromname+" <"+fromemail+">"
    toaddrs = [toname+" <"+toemail+">"]
    msg = "From: "+fromaddr+"\nTo: "+toemail+"\nMIME-Version: 1.0\nContent-type: text/plain\nSubject: "+subject+"\n"+body

    # Credentials (if needed)
    username = fromemail
    password = password

    # The actual mail send
    try:
        server = smtplib.SMTP('smtp.gmail.com:587')
        server.starttls()
        server.login(username,password)
        server.sendmail(fromaddr, toaddrs, msg)
        server.quit()       
        print "success"
    except smtplib.SMTPException:
        print "failure"

fromname = "Your Name"
fromemail = "yourgmailaccount@gmail.com"        
toname = "Recipient"
toemail = "recipient@other.com"
subject = "Test Mail"
body = "Body....."

notify(fromname, fromemail, toname, toemail, subject, body, password)